← IMC Interview Insights

IMC·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Apr 2026

Summary

Got a coding question from IMC for a software engineer role, purely algorithmic, no behavioral stuff at least in this round. The problem was more involved than it looked at first glance and the efficiency constraint is where it gets tricky.

Questions Asked (1)

Q1

A pharma company ships liquid medicine and has multiple container sets to choose from. Given a list of order volumes and several sets of container capacities, you must pick exactly one set that can fulfill all orders with minimum total waste. For each order, you use the smallest container that fits (exact match = zero waste). If a set can't cover some order, it's invalid. Return the index of the best set, or -1 if none work. Ties go to the lower index.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

The naive approach is obvious, loop over every order for every set and do a linear scan for the right container.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

First, clarify the problem constraints and edge cases (e.g., order volumes, container capacities, exact match, invalid sets). Then, outline a brute-force solution that iterates through each container set, checks validity, and computes total waste using binary search for efficiency. Finally, discuss potential optimizations and trade-offs, such as sorting capacities and early termination.

Pro tip: Demonstrate awareness of real-world constraints: in pharma, waste minimization is critical due to cost and regulatory factors, so emphasize exact matches and efficient search. Also, mention that ties are resolved by index, so iterate in order and update only when strictly better.

1. Clarify requirements and edge cases

Ask about input sizes, whether container capacities are sorted, if multiple containers can be used per order (no, exactly one), and what constitutes waste (unused capacity). Confirm that invalid sets are those where no container fits an order.

2. Design brute-force approach

For each container set, iterate through orders. For each order, find the smallest container that fits (using binary search if capacities are sorted). If none fits, mark set invalid. Otherwise, accumulate waste (container capacity - order volume).

3. Optimize and analyze complexity

Sort each container set's capacities once. For each order, binary search takes O(log m) where m is number of containers. Total per set: O(n log m). Overall: O(k * n log m) where k is number of sets. Discuss if pre-sorting all sets is beneficial.

4. Handle ties and return result

Track the minimum total waste and the corresponding set index. Since ties go to lower index, only update when waste is strictly less than current minimum. Return -1 if no valid set.

5. Test with examples and edge cases

Walk through a simple example, test exact matches, invalid sets, multiple sets with same waste, and large inputs to ensure efficiency. Mention potential pitfalls like integer overflow in waste sum.

Key Points to Mention

  • Binary search for efficient smallest container lookup
  • Sorting container capacities for each set
  • Validity check: every order must have a fitting container
  • Waste calculation: sum of (container capacity - order volume)
  • Tie-breaking: prefer lower index, so strict inequality when updating minimum
  • Time complexity: O(k * n log m) and potential optimizations

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.