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Grammarly·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

Grammarly SWE coding round, one question on string manipulation with a stack-based solution. Pretty clean problem once you see the pattern.

Questions Asked (1)

Q1

Given a string and an integer k, repeatedly remove k adjacent identical characters until no more removals are possible. Return the resulting string.

Algorithms & Data Structures
Author's notes

The naive approach of scanning and rebuilding the string in a loop will time out, which I almost went down before catching myself.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints (e.g., string length, character set, k value) and discuss edge cases. Then propose an efficient stack-based solution that simulates the removal process in O(n) time, explaining how to track counts of consecutive identical characters. Finally, analyze time and space complexity and consider alternative approaches like recursion or two-pointer techniques.

Pro tip: Mention that a naive recursive approach can be inefficient due to repeated scans; instead, emphasize the stack-based method which handles the problem in a single pass. Also, note that the problem is similar to 'remove adjacent duplicates' but with a count threshold, and discuss how to handle cases where removals create new adjacent duplicates.

1. Understand the problem and constraints

Ask clarifying questions about input size, character set, and k value. Confirm that removals are applied repeatedly until no more are possible, and that the result should be the final string after all removals.

2. Discuss brute force and its limitations

Mention that a naive approach of repeatedly scanning the string and removing k identical characters would be O(n^2) or worse. Explain why it's inefficient for large inputs.

3. Propose an optimal stack-based solution

Use a stack to store pairs of (character, count). Iterate through the string, pushing characters and incrementing counts. When the count reaches k, pop the pair. This simulates the removal process in one pass.

4. Analyze complexity and edge cases

State that the time complexity is O(n) and space complexity is O(n) in the worst case. Discuss edge cases: k=1 (removes all characters), empty string, k larger than string length, and characters that become adjacent after removals.

5. Test with examples and conclude

Walk through a small example (e.g., s='deeedbbcccbdaa', k=3) to demonstrate the algorithm. Summarize the solution and mention potential optimizations or variations.

Key Points to Mention

  • Stack-based approach with character-count pairs for O(n) time complexity
  • Handling of cascading removals (new adjacent duplicates formed after removal)
  • Edge cases: k=1, k > string length, empty string, all characters identical
  • Time and space complexity analysis (O(n) time, O(n) space)
  • Comparison with naive recursive approach and why it's inefficient
  • Potential follow-up: how to modify if k is variable per character or if removals are not limited to identical characters

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.