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Amazon·Software Engineer·Onsite - Coding / Algorithms·Intermediate

Intermediate
Apr 2026

Summary

Amazon SWE coding round with one string manipulation problem. Not a ton of context shared but the problem itself is tricky enough that it's worth writing up.

Questions Asked (1)

Q1

Given a string, find the lexicographically smallest string that is both greater than the input and has no two adjacent characters that are the same.

Algorithms & Data Structures
Author's notes

The examples help a lot here.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints and edge cases, then propose a greedy algorithm that scans from the right to find the rightmost position where you can increment a character while maintaining the no-adjacent-equal property. After incrementing, fill the suffix with the smallest possible characters, ensuring no two adjacent characters are the same.

Pro tip: Demonstrate awareness of edge cases like when the input is already the largest possible string (e.g., all 'z's) and discuss the time complexity (O(n)) and space complexity (O(n) or O(1) if modifying in place).

1. Clarify constraints and edge cases

Ask about the character set (e.g., lowercase letters), string length, and whether the input can be empty. Discuss edge cases like no valid string exists (e.g., 'zzz').

2. Identify the rightmost incrementable position

Scan from right to left to find the first character that can be incremented without violating the no-adjacent-equal rule with its left neighbor and while allowing a valid suffix.

3. Increment and construct the smallest suffix

Increment the character at that position, then fill the remaining positions with the smallest possible characters (e.g., 'a', 'b') ensuring no two adjacent characters are equal.

4. Handle no valid string case

If no such position exists, return an empty string or indicate that no valid string exists, depending on the problem requirements.

5. Analyze complexity and test

State the time and space complexity, and walk through examples to verify correctness, including edge cases.

Key Points to Mention

  • Greedy approach: modify the rightmost possible character to minimize the increase.
  • Maintain the no-adjacent-equal constraint during both increment and suffix filling.
  • Use a helper function to find the smallest valid character for a position given its left neighbor.
  • Time complexity: O(n) with a single pass for finding the position and another for filling the suffix.
  • Space complexity: O(n) for the output string, or O(1) if modifying in place.
  • Edge cases: empty string, all 'z's, strings where no valid answer exists.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.