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Google·Software Engineer·Onsite - Coding / Algorithms·Intermediate

Intermediate
Jun 2026

Summary

Google SWE coding round with a necklace string problem that looks deceptively clean on the surface but has some real edge case nastiness once you start thinking about the cut assignments.

Questions Asked (1)

Q1

Given a string of 'D' and 'R' characters forming a necklace where the total count of D equals the total count of R, split the necklace into two shares using at most two cuts so that each person's combined segments have an equal number of D's and R's.

Algorithms & Data Structures
Author's notes

I stared at this longer than I should have before realizing it's fundamentally a prefix sum problem.

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AI HintsAI Generated

Suggested Approach

First, clarify the problem and constraints, then propose a solution using prefix sums to track the balance of D and R. Since the total counts are equal, there exists a point where the balance is zero; use at most two cuts to split the necklace into two parts with equal counts.

Pro tip: Mention that the problem is equivalent to finding a contiguous segment with equal D and R, and that two cuts are sufficient because the total balance is zero. This shows deep insight and avoids overcomplicating the solution.

1. Clarify the problem

Confirm that the necklace is a circular string, cuts can be at any positions, and each person must receive segments whose combined D and R counts are equal. Ask if the shares must be contiguous or can be multiple segments.

2. Define balance and prefix sums

Assign +1 to D and -1 to R (or vice versa). Compute prefix sums around the circle. The total sum is 0, so there exists an index where the prefix sum repeats.

3. Find a zero-sum segment

Use a hash map to find two indices with the same prefix sum. The segment between them has equal D and R. This segment can be one person's share, and the remaining necklace (also balanced) is the other person's share.

4. Determine cuts

The two cuts are at the boundaries of the zero-sum segment. If the segment is the entire necklace, one cut suffices; otherwise, two cuts are needed.

5. Handle edge cases

Consider cases where the zero-sum segment is the whole necklace (one cut) or where multiple solutions exist. Ensure the solution works for any valid input.

Key Points to Mention

  • Prefix sum technique to track balance of D and R
  • Hash map to store first occurrence of each prefix sum
  • Circular nature of the necklace and how to handle it (e.g., by doubling the string or using modulo)
  • Proof that two cuts are always sufficient when total counts are equal
  • Time and space complexity: O(n) time, O(n) space
  • Edge cases: all D's and R's alternating, or already balanced segments

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.