My first instinct was a hashmap from index to value, which is fine, but then they asked what happens when one vector is dense and the other is sparse.
Start by clarifying the problem constraints and then propose a hash map (dictionary) representation that stores only non-zero indices and their values. Implement the dot product by iterating over the smaller map and checking for matching indices in the larger map, ensuring efficiency regardless of sparsity patterns. Finally, analyze the time and space complexity for both construction and dot product, highlighting the benefits of this sparse representation.
Pro tip: Mention that you would iterate over the smaller of the two vectors' non-zero entries to minimize lookups, and discuss potential trade-offs between hash maps and sorted arrays for different access patterns.
Confirm the vector length, sparsity, and expected operations. Ask about the need for updates, thread safety, or other operations beyond dot product.
Propose using a hash map (dictionary) mapping index to value for non-zero elements. Explain why this is efficient for sparse vectors and how it handles construction from a dense array.
Iterate over the smaller map's entries, and for each index, check if it exists in the other map. Accumulate the product of values. This minimizes lookups and handles different sparsity patterns.
State that construction takes O(n) time to scan the dense array and O(k) space for k non-zeros. Dot product takes O(min(k1, k2)) time and O(1) extra space, where k1 and k2 are the number of non-zeros in each vector.
Mention that sorted arrays could allow two-pointer intersection in O(k1 + k2) time but with O(k) space and slower updates. Hash maps offer O(1) average lookups and are simpler for dynamic updates.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.