← Capital One Interview Insights
Seemed easy at first and I jumped straight into iterating the array, which was fine.
Clarify the problem constraints and edge cases, then propose a single-pass O(n) solution that counts elements greater than and less than the target while ignoring equals. Compare the counts and return the appropriate string, discussing time and space complexity.
Pro tip: Mention that you can early-exit if one count exceeds the remaining elements, but note that a full pass is still O(n) and may be simpler. Also, explicitly state that you ignore elements equal to the target to avoid off-by-one errors.
Ask about input size, data types, and whether the array can be empty or contain duplicates. Confirm that equal elements are excluded from both counts.
Initialize two counters, greater and smaller, to zero. Iterate through each element: if element > target, increment greater; if element < target, increment smaller; otherwise do nothing.
After the loop, compare greater and smaller. Return 'greater' if greater > smaller, 'smaller' if smaller > greater, and 'tie' if they are equal.
State that time complexity is O(n) and space is O(1). Optionally mention early termination if one count exceeds the number of remaining elements, but note it doesn't change worst-case complexity.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.