I knew the min-heap approach going in but fumbled a bit explaining why it's O(log k) per call.
Start by clarifying the problem and constraints, then propose a min-heap solution that stores the current head of each stream. Walk through the algorithm step-by-step, analyze the time complexity of each next() call, and discuss edge cases like empty or finite streams.
Pro tip: Mention that you can optimize by only adding non-empty streams to the heap initially and after each pop, and highlight that the heap size is bounded by the number of streams, making it efficient for many streams.
Ask about the number of streams, whether they can be empty, if streams are finite, and if there are memory constraints. Confirm that next() should return the smallest value and advance that stream.
Use a min-heap (priority queue) to store the current head of each non-empty stream. Each heap element contains the value and a reference to its stream. Initialize the heap with the first element of each stream that hasNext().
For next(): pop the minimum from the heap, advance that stream, and if the stream still hasNext(), push its new head into the heap. Return the popped value. For hasNext(): return true if the heap is not empty.
Each next() call involves a heap pop and possibly a heap push, both O(log k) where k is the number of streams. Overall, for n total elements, total time is O(n log k). Space is O(k) for the heap.
Discuss handling empty streams (skip them), finite streams (remove from heap when exhausted), and all streams empty (return null or throw exception). Also consider if streams can be infinite, but the algorithm still works.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.