Took me longer than I'd like to admit to land on the self-join approach.
Clarify the definition of overlap (e.g., strict or inclusive) and whether a session can overlap with itself. Then use a self-join to count overlaps for each session, and select the session with the maximum count, handling ties appropriately.
Pro tip: Mention that you'd confirm the expected output for ties (e.g., return all tied sessions or just one) and discuss performance implications of the self-join on large datasets, suggesting an interval tree or sweep-line algorithm as an alternative.
Ask about the definition of overlap (strict vs. inclusive), whether a session can overlap with itself, and how to handle ties. Confirm the desired output format.
Use a self-join on the sessions table where sessions overlap if one starts before the other ends and ends after the other starts. Count overlaps per session.
Construct the query: SELECT s1.session_id, COUNT(*) AS overlap_count FROM sessions s1 JOIN sessions s2 ON s1.session_id != s2.session_id AND s1.start_time < s2.end_time AND s1.end_time > s2.start_time GROUP BY s1.session_id ORDER BY overlap_count DESC LIMIT 1;
Discuss how to modify the query to return all sessions with the maximum overlap count (e.g., using a subquery or window function) and consider sessions with zero overlaps.
Mention indexing on start_time and end_time, and note that for large datasets, a sweep-line algorithm can compute overlaps in O(n log n) time.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.