I knew the triangle inequality theorem but blanked on how to apply it efficiently.
First clarify the problem: return any three elements that can form a triangle, or all such triplets? Then explain the triangle inequality and the efficient O(n log n) sorting-based approach that checks consecutive triplets. If needed, discuss the brute-force O(n^3) method and why it's suboptimal.
Pro tip: Mention that after sorting, you only need to check consecutive triplets because if a valid triangle exists, one will be found among adjacent elements. This demonstrates deep understanding and avoids unnecessary complexity.
Ask whether to return any valid triplet or all triplets, and whether the array can have duplicates or negative numbers. This shows attention to detail and avoids misinterpretation.
State that for sides a ≤ b ≤ c, a triangle is valid if and only if a + b > c. This is the core condition to check.
Describe the naive O(n^3) solution that checks all triplets, and note its inefficiency for large arrays.
Sort the array in O(n log n) and then check consecutive triplets (i, i+1, i+2) for the condition a + b > c. If found, return that triplet; otherwise, no valid triangle exists.
Discuss time complexity O(n log n) and space O(1) or O(n) depending on sorting. Mention edge cases like arrays with fewer than 3 elements, all zeros, or negative numbers.
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