This is just the binomial pmf so I wasn't stressed, but I fumbled slightly explaining why the combinations term is there.
Start by identifying the distribution: for a fair coin, the number of heads follows a Binomial(N, 0.5) distribution, so the probability is C(N,k) * (0.5)^N. For a biased coin, it's Binomial(N, p) with probability C(N,k) * p^k * (1-p)^(N-k). Explain the assumptions and mention that the binomial coefficient counts the number of ways to choose which tosses are heads.
Pro tip: Emphasize that the binomial coefficient accounts for the orderings of heads and tails, and note that for large N, you might use the normal approximation or Poisson approximation when p is small, showing practical awareness.
Let X be the number of heads in N independent tosses. For a fair coin, X ~ Binomial(N, 0.5); for a biased coin, X ~ Binomial(N, p).
For a fair coin, P(X=k) = C(N,k) * (0.5)^N. For a biased coin, P(X=k) = C(N,k) * p^k * (1-p)^(N-k). Explain that C(N,k) counts the number of sequences with exactly k heads.
Mention independence of tosses and that k must be between 0 and N. If k is outside this range, the probability is 0.
For large N, the binomial can be approximated by a normal distribution (with mean Np and variance Np(1-p)) or by a Poisson distribution when p is small and N large. This shows deeper understanding.
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Blanked for a second on how to phrase the standardization step cleanly.
Start by stating the goal: compute the probability that X falls between a and b. Then explain the standardization process: subtract the mean and divide by the standard deviation to convert X to a standard normal variable Z. Finally, express the probability in terms of Z and use the standard normal CDF to compute it.
Pro tip: Emphasize that standardization allows using a single table or function for all normal distributions, and mention that in practice you'd use software like Python's scipy.stats.norm.cdf rather than tables. This shows practical awareness.
Clearly define that you want to find P(a < X < b) where X ~ N(μ, σ²).
Transform the inequality by subtracting μ and dividing by σ: P((a-μ)/σ < (X-μ)/σ < (b-μ)/σ).
Define Z = (X-μ)/σ, which follows a standard normal distribution N(0,1).
Rewrite the probability as P((a-μ)/σ < Z < (b-μ)/σ).
Use the standard normal CDF Φ to compute Φ((b-μ)/σ) - Φ((a-μ)/σ).
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