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Tesla·Software Engineer·Online Assessment (OA)·Intermediate

Intermediate
Jul 2026

Summary

Tesla SWE interview that was basically a gauntlet of classic algorithm problems back to back. Nine questions total, covering everything from string parsing to graph traversal. Felt more like an OA than a conversation.

Questions Asked (9)

Q1

Implement an expression evaluator that parses a string of digits and operators (+, -, *, /) with spaces and returns the integer result. No parentheses. Division truncates toward zero. Do it in a single pass.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

The single-pass constraint is what makes this annoying.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and edge cases first, then propose a single-pass solution using a stack or running total with a pending operator. Walk through the algorithm with a concrete example, emphasizing how to handle operator precedence and integer division truncation toward zero.

Pro tip: Mention that you can avoid a stack by maintaining a running result and a 'last term' to handle precedence, which reduces space complexity to O(1). Also, explicitly state how you handle negative division truncation (e.g., -3/2 = -1) to show attention to detail.

1. Clarify requirements and edge cases

Ask about input format (spaces, multi-digit numbers), division truncation, and potential overflow. Confirm that no parentheses are allowed and that operators are binary.

2. Choose data structures and algorithm

Decide between a stack-based approach or a running total with a 'last term' for O(1) space. Explain how to handle operator precedence by deferring addition/subtraction until after multiplication/division.

3. Walk through the algorithm

Describe parsing the string character by character, building numbers, and applying operators. Use a concrete example like '3+2*2' to illustrate the steps.

4. Handle division and truncation

Explain how to implement integer division that truncates toward zero, especially for negative numbers, and mention potential pitfalls like integer overflow.

5. Analyze complexity and test

State time and space complexity (O(n) time, O(1) or O(n) space depending on approach). Suggest test cases including single number, multiple operators, and negative results.

Key Points to Mention

  • Single-pass parsing with O(n) time complexity
  • Handling operator precedence without parentheses using a stack or last term
  • Integer division truncation toward zero and negative number handling
  • Edge cases: leading/trailing spaces, multi-digit numbers, division by zero
  • Space complexity trade-offs: stack vs. O(1) running total
  • Potential integer overflow and use of appropriate data types

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given an array of positive integers, count how many index triplets (i < j < k) form the sides of a valid non-degenerate triangle. Aim for O(n^2) after sorting.

Algorithms & Data Structures
Author's notes

Sort first, then for each pair (i, k) binary search or use a two-pointer to count valid j values.

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AI HintsAI Generated

Suggested Approach

Sort the array first, then for each pair (i, j) with i < j, use binary search to find the largest k such that a[i] + a[j] > a[k]. The number of valid triplets for this pair is k - j, and summing over all pairs gives the total count in O(n^2 log n), which can be optimized to O(n^2) with a two-pointer approach.

Pro tip: Mention that sorting is safe because triangle validity depends only on side lengths, not order. Also, emphasize that the two-pointer method avoids binary search overhead, achieving true O(n^2) time.

1. Sort the array

Sort the array in non-decreasing order. This allows us to use the triangle inequality efficiently and ensures that for any i < j < k, we only need to check a[i] + a[j] > a[k].

2. Fix the largest side

Iterate k from 2 to n-1, treating a[k] as the largest side of the triangle. For each k, find all pairs (i, j) with i < j < k such that a[i] + a[j] > a[k].

3. Use two pointers

For each k, initialize i = 0 and j = k-1. While i < j, if a[i] + a[j] > a[k], then all pairs (i, j), (i+1, j), ..., (j-1, j) are valid, so add (j - i) to the count and decrement j. Otherwise, increment i.

4. Sum and return

Accumulate the counts for all k and return the total number of valid triplets. The overall time complexity is O(n^2) due to the nested loops with two pointers.

Key Points to Mention

  • Triangle inequality: for sorted sides a ≤ b ≤ c, only need to check a + b > c.
  • Sorting the array first is crucial for the two-pointer technique and does not affect the count.
  • Two-pointer approach reduces the inner loop from O(n) to O(1) per k, achieving O(n^2) overall.
  • Handle edge cases: empty array, array with fewer than 3 elements, and duplicate values.
  • Time complexity: O(n^2) after O(n log n) sorting; space complexity: O(1) extra if sorting in place.
  • Explain why the two-pointer condition works: if a[i] + a[j] > a[k], then for any i' between i and j-1, a[i'] + a[j] ≥ a[i] + a[j] > a[k].

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Merge a list of closed intervals, combining any that overlap or share an endpoint, and return the result sorted.

Algorithms & Data Structures
Author's notes

Sort by start time, then sweep.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the input format and edge cases, then propose sorting the intervals by start time and merging in a single pass. Explain the O(n log n) time and O(n) space complexity, and walk through a concrete example to demonstrate correctness.

Pro tip: Mention that sorting is essential for efficiency, but also note that if the input is already sorted or nearly sorted, you can optimize by using insertion sort or skipping the sort. This shows awareness of real-world data characteristics.

1. Clarify requirements and edge cases

Ask about input format (list of pairs, sorted or unsorted), whether intervals are inclusive, and how to handle empty input or single interval. Confirm that merging should combine overlapping or touching intervals.

2. Outline the algorithm

Propose sorting intervals by start time, then iterating through them while maintaining a current merged interval. If the next interval overlaps or touches the current one, extend the end; otherwise, add the current to the result and start a new one.

3. Analyze complexity

State that sorting takes O(n log n) time and the merge pass takes O(n), so overall O(n log n) time. Space is O(n) for the output (or O(1) extra if merging in-place, but typically O(n) for result).

4. Walk through an example

Use a small example like [[1,3],[2,6],[8,10],[15,18]] to show how the algorithm merges [1,3] and [2,6] into [1,6], and produces [[1,6],[8,10],[15,18]]. This demonstrates understanding and catches off-by-one errors.

5. Discuss edge cases and optimizations

Mention handling of empty input, single interval, intervals that are already sorted, and intervals that share an endpoint (e.g., [1,4] and [4,5] should merge). Optionally, discuss in-place merging if the input can be modified.

Key Points to Mention

  • Sorting by start time is crucial for the greedy merge approach.
  • Overlap condition: next.start <= current.end (including equality for shared endpoints).
  • Time complexity: O(n log n) due to sorting; space complexity: O(n) for output.
  • Edge cases: empty list, single interval, all intervals overlapping, no overlaps.
  • Use of a result list and updating the last interval's end when merging.
  • Potential optimization if input is already sorted (O(n) time).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

Count the number of connected land clusters in a grid of '1's and '0's, where connectivity is 4-directional.

Algorithms & Data Structures
Author's notes

Classic islands problem.

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AI HintsAI Generated

Suggested Approach

Treat the grid as a graph and use DFS or BFS to explore each unvisited land cell, marking all connected land cells as visited. Each time you start a traversal from an unvisited land cell, increment the island count. Ensure you handle edge cases like empty grid or no land.

Pro tip: Clarify whether modifying the input grid is acceptable; if not, use a separate visited matrix. Also, discuss trade-offs between DFS (recursive, risk of stack overflow) and BFS (iterative, uses queue) especially for large grids.

1. Understand the problem

Confirm that connectivity is 4-directional (up, down, left, right) and that clusters are maximal connected components of '1's. Ask about grid size limits and whether the grid can be modified.

2. Choose traversal method

Decide between DFS (recursive or iterative) and BFS. Consider space complexity and potential stack overflow for large grids; BFS with a queue is often safer.

3. Implement traversal

Iterate through each cell; when you find an unvisited '1', increment count and start traversal to mark all connected '1's as visited (e.g., set to '0' or use a visited set).

4. Handle edge cases

Check for empty grid, grid with no land, or all land. Ensure boundary conditions are handled in neighbor checks.

5. Analyze complexity

State time complexity O(M*N) and space complexity O(M*N) in worst case (e.g., all land) due to recursion stack or queue.

Key Points to Mention

  • 4-directional connectivity (up, down, left, right)
  • DFS vs BFS trade-offs (recursion depth vs queue memory)
  • In-place modification vs separate visited matrix
  • Time complexity O(M*N) and space complexity O(M*N)
  • Edge cases: empty grid, no land, all land
  • Potential for stack overflow with recursive DFS on large grids

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q5

Find the smallest missing positive integer in an unsorted array. Must run in O(n) time and O(1) extra space.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This one tripped me up more than I expected.

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AI HintsAI Generated

Suggested Approach

Use the array itself as a hash table by placing each number in its correct index (e.g., value x at index x-1) through cyclic swaps. Then scan the array to find the first index where the value is not index+1; that index+1 is the smallest missing positive. This achieves O(n) time and O(1) extra space.

Pro tip: Clarify upfront that the array is modifiable; if not, the O(1) space constraint is impossible. Also, mention that you handle edge cases like all numbers present (answer n+1) and ignore non-positive or out-of-range values.

1. Clarify constraints and edge cases

Confirm that the array can be modified in-place and discuss edge cases such as empty array, all negatives, or all numbers 1..n present.

2. Explain the cyclic sort idea

Describe how to iterate through the array and swap each positive integer x (where 1 <= x <= n) into its correct position at index x-1, ignoring values outside this range.

3. Perform the in-place rearrangement

Walk through the swapping process, ensuring each number is placed correctly. Use a while loop to continue swapping until the current element is in the right place or out of range.

4. Scan for the first missing positive

After rearrangement, iterate through the array and return the first index i where nums[i] != i+1; if all are correct, return n+1.

5. Analyze complexity and trade-offs

Conclude that the algorithm runs in O(n) time (each element swapped at most once) and O(1) extra space, and discuss why alternative approaches (sorting, hash set) fail the constraints.

Key Points to Mention

  • In-place cyclic sort to use the array as a hash table
  • Ignoring non-positive numbers and numbers greater than n
  • Time complexity O(n) because each element is swapped at most once
  • Space complexity O(1) as no additional data structures are used
  • Edge cases: empty array, all negatives, all positives 1..n present
  • Comparison with other approaches (sorting O(n log n), hash set O(n) space)

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q6

Return the maximum sum of any non-empty contiguous subarray. Optionally return the subarray's start and end indices.

Algorithms & Data Structures
Author's notes

Kadane's algorithm.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints (e.g., array size, element types, whether indices are required) and then present Kadane's algorithm as the optimal O(n) solution. Explain the algorithm step-by-step, handle edge cases like all negative numbers, and if indices are needed, describe how to track the start and end positions.

Pro tip: Mention that Kadane's algorithm is a dynamic programming approach and discuss how it can be adapted for circular arrays or other variants, showing depth beyond the basic problem.

1. Clarify requirements and constraints

Ask about input size, possible values (negative, zero, positive), and whether returning indices is required. This ensures you address the exact problem and edge cases.

2. Explain the brute-force approach and its complexity

Briefly mention that checking all subarrays takes O(n^2) or O(n^3) time, which is inefficient for large inputs, motivating a better solution.

3. Present Kadane's algorithm

Describe the O(n) dynamic programming solution: maintain current_sum and max_sum, updating current_sum as max(arr[i], current_sum + arr[i]) and max_sum as max(max_sum, current_sum).

4. Extend to track indices (if required)

Explain how to track start and end indices by recording the start when current_sum resets and updating the end when max_sum changes.

5. Discuss edge cases and test

Cover cases like all negative numbers (return the maximum single element), empty array (if allowed), and single element. Walk through a small example to verify.

Key Points to Mention

  • Kadane's algorithm is a dynamic programming approach with O(n) time and O(1) space.
  • The recurrence relation: current_sum = max(arr[i], current_sum + arr[i]).
  • Handling all-negative arrays: initialize max_sum to the first element or negative infinity.
  • Tracking indices: update start index when current_sum resets to arr[i], and update end index when max_sum updates.
  • Alternative approaches like divide and conquer (O(n log n)) or prefix sums, but Kadane's is optimal.
  • Potential follow-up: maximum sum circular subarray, which requires a variation of Kadane's.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q7

Given an array of daily stock prices, find the maximum profit from a single buy followed by a single sell. Return 0 if no profitable trade exists.

Algorithms & Data Structures
Author's notes

Track the running minimum as you scan and update max profit at each step.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and edge cases, then propose an efficient one-pass solution that tracks the minimum price seen so far and the maximum profit. Explain the algorithm step-by-step, analyze its time and space complexity, and test it with examples including edge cases.

Pro tip: Demonstrate awareness of real-world constraints by mentioning that stock prices are typically positive and that the solution should handle large datasets efficiently. Also, proactively discuss potential follow-ups like multiple transactions or handling streaming data.

1. Clarify requirements and edge cases

Ask about input size, data types, and whether prices can be zero or negative. Confirm that only one buy and one sell are allowed, and that the buy must occur before the sell.

2. Outline a brute-force approach

Briefly mention that a naive O(n^2) solution checks all pairs of buy and sell days, but this is inefficient for large inputs.

3. Propose an optimal one-pass solution

Explain that you can iterate through the array once, keeping track of the minimum price seen so far and the maximum profit achievable. Update these variables at each step.

4. Analyze complexity and test

State that the time complexity is O(n) and space complexity is O(1). Walk through a few examples, including cases where no profit is possible (return 0).

5. Discuss potential follow-ups

Mention extensions like multiple transactions, transaction fees, or handling streaming data, showing depth of understanding.

Key Points to Mention

  • Time complexity: O(n) single pass
  • Space complexity: O(1) constant extra space
  • Tracking minimum price and maximum profit
  • Handling edge cases: empty array, single element, decreasing prices
  • Returning 0 when no profit is possible
  • Real-world relevance: efficient for large datasets

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q8

Find the length of the longest sequence of consecutive integers in an unsorted array. Target average O(n) using hashing.

Algorithms & Data Structures
Author's notes

Put everything in a hash set, then for each number that has no left neighbor (n-1 not in set), walk forward counting the streak.

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AI HintsAI Generated

Suggested Approach

Use a hash set to store all elements for O(1) lookups. For each number, check if it's the start of a sequence (i.e., num-1 not in set), then count consecutive numbers. This ensures each number is visited at most twice, achieving O(n) average time.

Pro tip: Mention that you only start counting from numbers that are sequence starts to avoid redundant work, and discuss handling duplicates and edge cases like empty arrays. This shows attention to efficiency and robustness.

1. Clarify and Confirm

Ask clarifying questions: Are there duplicates? Can the array be empty? What are the constraints on integer values? Confirm that the expected time complexity is O(n) average.

2. Outline the Hash Set Approach

Explain that you'll insert all elements into a hash set for O(1) lookups. Then iterate through the array, and for each element, check if it's the start of a sequence by verifying if num-1 is not in the set.

3. Count Consecutive Numbers

For each sequence start, increment a counter while the next consecutive number exists in the set. Keep track of the maximum length found.

4. Analyze Complexity and Edge Cases

State that each element is visited at most twice (once in the initial loop, once during counting), so time is O(n) average. Space is O(n) for the set. Discuss edge cases: empty array, all duplicates, negative numbers.

5. Test with Examples

Walk through a small example, e.g., [100, 4, 200, 1, 3, 2] to show the algorithm finds the longest sequence [1,2,3,4] of length 4. Also test with duplicates and negative numbers.

Key Points to Mention

  • Hash set for O(1) lookups
  • Only start counting from sequence starts (num-1 not in set)
  • Each element visited at most twice, ensuring O(n) average time
  • Space complexity O(n) due to hash set
  • Handling duplicates by using a set (duplicates ignored)
  • Edge cases: empty array, single element, all elements same, negative numbers

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q9

Given a number of courses and prerequisite pairs, determine if all courses can be completed. If yes, return a valid ordering. Handle up to 100,000 nodes and edges.

Algorithms & Data StructuresSystem Design
Author's notes

Topological sort via Kahn's algorithm (BFS with in-degree tracking).

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AI HintsAI Generated

Suggested Approach

Model the courses and prerequisites as a directed graph, then perform a topological sort using Kahn's algorithm (BFS) or DFS. If a cycle exists, return false; otherwise, return the topological order. Ensure the solution handles large inputs efficiently with O(V+E) time and space.

Pro tip: Mention that Kahn's algorithm naturally detects cycles by checking if the processed nodes count equals the total number of courses, and it avoids recursion depth issues for large graphs. Also, discuss how this approach scales to 100,000 nodes and edges with linear time complexity.

1. Understand the problem

Clarify that the input is a number of courses and a list of prerequisite pairs, and the goal is to determine if all courses can be completed and return a valid order if possible. Recognize this as a topological sorting problem on a directed graph.

2. Choose the algorithm

Select either Kahn's algorithm (BFS-based) or DFS-based topological sort. For large graphs, Kahn's algorithm is often preferred due to its iterative nature and explicit cycle detection.

3. Implement the solution

Build the graph and compute in-degrees for each node. Use a queue to process nodes with zero in-degree, appending them to the order and reducing in-degrees of their neighbors. If the order contains all nodes, return it; otherwise, return an empty array or false.

4. Analyze complexity and edge cases

State that the time complexity is O(V+E) and space complexity is O(V+E). Discuss edge cases such as no prerequisites, disconnected graphs, and cycles. Mention that the solution handles up to 100,000 nodes and edges efficiently.

Key Points to Mention

  • Topological sorting is the core concept for ordering courses with prerequisites.
  • Kahn's algorithm uses in-degrees and a queue to process nodes, naturally detecting cycles.
  • DFS-based topological sort can also be used, but recursion depth may be a concern for large graphs.
  • Time and space complexity are O(V+E), which is optimal for this problem.
  • Cycle detection is crucial: if a cycle exists, no valid ordering is possible.
  • Handling large inputs requires efficient data structures like adjacency lists and arrays for in-degrees.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.