My first instinct was to just compute slopes between consecutive points and compare them, which is the obvious wrong answer the moment you think about vertical lines or precision loss.
Start by clarifying the problem: we need to remove redundant collinear points from a path while preserving endpoints and direction changes. Explain that collinearity can be checked using the cross product of vectors formed by consecutive points, and that using integer arithmetic avoids floating-point precision issues. Then outline an O(n) algorithm that iterates through the points and keeps only those that are not collinear with their neighbors.
Pro tip: Mention that you would handle edge cases such as duplicate points, paths with fewer than 3 points, and the importance of preserving the original order. Also, note that the cross product sign indicates the direction of the turn, which can be used to detect collinearity.
Confirm that the input is a sequence of 2D integer coordinates, and the output should be a compressed sequence preserving the path shape. Ask about edge cases like duplicate points or very short paths.
Describe how to use the cross product of vectors (B-A) and (C-B) to determine if three points A, B, C are collinear. Emphasize that using integer arithmetic avoids floating-point errors.
Propose an O(n) single-pass algorithm: initialize a result list with the first point, then for each subsequent point, check if it forms a straight line with the last two points in the result. If not, add it to the result.
Address handling of duplicate points, paths with fewer than 3 points, and potential memory optimizations. Mention that the algorithm preserves the original order and endpoints.
State that the time complexity is O(n) and space complexity is O(n) for the output. Discuss trade-offs: integer cross product is exact but may overflow for very large coordinates; consider using larger integer types if needed.
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