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LinkedIn·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

LinkedIn coding round, looked like a straightforward frequency problem but the tie-breaking condition is where people trip up. Worth knowing your heap mechanics cold before walking in.

Questions Asked (1)

Q1

Given a list of words and an integer k, return the k most frequent words ordered by frequency descending, with ties broken alphabetically.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

The frequency counting part is fine, everyone gets that.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints (e.g., input size, definition of word, case sensitivity) and then propose a solution using a hash map to count frequencies, followed by sorting with a custom comparator that orders by frequency descending and lexicographically ascending for ties. Discuss time and space complexity, and consider alternative approaches like a heap for large k or when k is small relative to unique words.

Pro tip: Mention that you would use a min-heap of size k to achieve O(n log k) time, which is more efficient than sorting all unique words when k is much smaller than the number of unique words. Also, clarify edge cases like empty input, k larger than unique words, and how to handle case sensitivity.

1. Clarify requirements and constraints

Ask about input size, definition of a word, case sensitivity, and whether k can exceed the number of unique words. This ensures you handle edge cases correctly.

2. Count frequencies

Use a hash map to count the frequency of each word in O(n) time. This is the standard first step for frequency-based problems.

3. Select top k words

Choose between sorting all unique words (O(m log m)) or using a min-heap of size k (O(m log k)), where m is the number of unique words. Discuss trade-offs based on constraints.

4. Define ordering and handle ties

For sorting, use a comparator that sorts by frequency descending and alphabetically ascending for ties. For heap, define a custom comparator that keeps the k most frequent words with correct tie-breaking.

5. Analyze complexity and test edge cases

State time and space complexity, and walk through edge cases like empty input, k=0, k > unique words, and words with same frequency.

Key Points to Mention

  • Hash map for frequency counting with O(n) time and O(m) space.
  • Sorting approach: O(m log m) time, where m is number of unique words.
  • Heap approach: O(m log k) time using a min-heap of size k, efficient when k << m.
  • Custom comparator for tie-breaking: frequency descending, then lexicographical ascending.
  • Edge cases: empty input, k=0, k > unique words, case sensitivity, and non-alphanumeric characters.
  • Trade-offs: sorting is simpler but less efficient for small k; heap is more efficient but requires careful comparator implementation.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.