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Amazon·Software Engineer·Online Assessment (OA)·Intermediate

Intermediate
Jun 2026

Summary

Amazon OA for a SWE role, one problem involving wildcards in a binary string and counting subsequence pairs to maximize a weighted error score. Tricky modular arithmetic involved and the constraints weren't even given, which was a bit annoying.

Questions Asked (1)

Q1

You're given a string of '0', '1', and '!' characters. Replace each '!' with either '0' or '1'. For the resulting binary string, count all index pairs (i < j) where s[i]='1' and s[j]='0' (call this count10) and pairs where s[i]='0' and s[j]='1' (call this count01). The total error is x * count10 + y * count01. Choose replacements to maximize this total and return it modulo 1,000,000,007.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I spent a good chunk of time just figuring out what the problem was actually asking because subsequence pairs vs subarrays is a distinction that bites you if you skim.

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AI HintsAI Generated

Suggested Approach

First, clarify the problem and constraints, then derive a dynamic programming solution that processes the string left to right while tracking the number of zeros and ones placed so far. For each '!', consider both choices and update the counts of count10 and count01 based on previously placed characters, maximizing the weighted sum. Finally, apply modulo 1,000,000,007 to the result.

Pro tip: Emphasize that the optimal replacement for each '!' can be decided greedily based on the current counts and weights, but be prepared to justify why a DP is needed if the greedy choice isn't locally optimal. Mention that modulo operations should be applied only at the end to avoid overflow and precision issues.

1. Clarify the problem and constraints

Restate the problem in your own words, confirm the definitions of count10 and count01, and ask about input size limits and modulo requirements.

2. Identify the objective and variables

Recognize that the total error is x*count10 + y*count01, and that each '!' replacement affects future counts. Define state variables such as number of zeros and ones placed so far.

3. Design a dynamic programming or greedy approach

Propose a DP that processes characters left to right, maintaining the maximum total error achievable for each possible count of zeros (or ones). For each '!', consider both choices and update counts accordingly.

4. Optimize and handle modulo

If the DP state space is too large, look for optimizations such as reducing dimensions or using a greedy strategy. Apply modulo 1,000,000,007 to the final answer.

5. Test with examples and edge cases

Walk through small examples (e.g., string with one '!', all '!', no '!') to verify the approach and discuss time/space complexity.

Key Points to Mention

  • Dynamic programming state definition: dp[i][j] = max error after processing first i characters with j zeros placed.
  • Transition for fixed characters: update count10 and count01 based on previous zeros/ones.
  • Transition for '!': try placing '0' or '1' and update counts accordingly.
  • Modulo arithmetic: apply modulo 1e9+7 only at the end or during addition to prevent overflow.
  • Time and space complexity: O(n^2) DP, can be optimized to O(n) with greedy if applicable.
  • Edge cases: empty string, all '!', no '!', extreme weights x and y.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.