I got the basic merge logic down pretty quick but then they kept pulling on edge cases.
Walk through a linear scan approach that processes intervals in three phases: those entirely before the new interval, those overlapping (which get merged), and those entirely after. Clearly state the O(n) time and O(n) space complexity, and explicitly address edge cases like empty input, insertion at start/end, and full containment.
Pro tip: Mention that since the input is sorted and non-overlapping, a linear scan is optimal—no need for binary search unless you're only finding the insertion point. Also, clarify that you're returning a new list to avoid mutating the input, which is often expected in production code.
Confirm the problem: intervals are sorted, non-overlapping, closed, and you need to insert and merge. Ask if the input can be modified or if a new list is preferred.
Explain that you'll iterate through intervals: first add all intervals that end before the new interval starts, then merge all overlapping intervals with the new one, then add the remaining intervals.
While merging, update the new interval's start to min(current.start, new.start) and end to max(current.end, new.end). Continue until an interval starts after the new interval ends.
State that time complexity is O(n) because each interval is visited once, and space complexity is O(n) for the output list (or O(1) extra if modifying in place).
Explicitly mention: empty input list, new interval before all, after all, completely contained within an existing interval, and completely containing existing intervals.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.