Took me a while to realize that a lot of machines in the middle can be redundant without affecting the total absolute difference sum.
First, clarify the problem and edge cases, then identify that the sum of absolute differences is invariant under removing elements that lie on a monotonic segment between two kept elements. The goal reduces to selecting a subsequence that preserves the total variation, which can be solved by dynamic programming or by finding the minimum number of local extrema (peaks and valleys) needed to maintain the sum.
Pro tip: Mention that the minimum number of machines corresponds to the number of local extrema in the array (including endpoints), as these are the only points where the direction of change reverses. This insight simplifies the problem and shows deep understanding.
Restate the problem to ensure clarity: we need the smallest subsequence (keeping order) with the same sum of absolute differences as the original array. Consider edge cases: array of length 1, all equal elements, strictly increasing/decreasing arrays.
The sum of absolute differences is the total variation. Removing an element that lies on a straight monotonic segment between two kept elements does not change the total variation. Thus, we only need to keep elements that are necessary to preserve the direction changes.
The minimal subsequence must include the first and last elements, and all local extrema (peaks and valleys) where the sign of the difference changes. Any other element can be removed without affecting the sum.
Count the number of local extrema plus the endpoints. If the array has no direction changes (monotonic), the minimum is 2 (or 1 if all elements are equal). If the array length is 1, return 1.
If the computed minimum is greater than the original length (which shouldn't happen), return the original length. Otherwise, return the count. Verify with examples.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.