I started with just left-slide since that felt easiest to reason about, got that working, then tried to rotate the board to reuse the same logic for other directions.
Start by explaining that you'll handle each direction by transforming the board so that sliding always occurs to the left, then applying a single slide-and-merge function, and finally reversing the transformation. Emphasize that the key is to process each row independently, merging adjacent equal tiles while ensuring each tile merges only once per move. Finally, discuss how to apply this to all four directions efficiently.
Pro tip: Mention that you can avoid duplicating logic for each direction by using board transformations (reverse rows, transpose) and that this approach reduces bugs and makes the code more maintainable. Also, note that you should handle the merge by iterating from the direction of movement to avoid double merges.
Confirm the rules: tiles slide as far as possible, merges happen only between two tiles of equal value, and each tile can merge only once per move. Discuss edge cases like multiple merges in a row (e.g., [2,2,2,2] -> [4,4]) and no movement.
Implement a function that slides and merges a single row to the left. This function will iterate through the row, combining adjacent equal tiles and shifting non-zero tiles to the left.
Use board transformations: for left, apply helper directly; for right, reverse each row, apply helper, then reverse back; for up, transpose the board, apply left helper, then transpose back; for down, transpose, reverse rows, apply helper, reverse rows, transpose back.
Write the code, ensuring that the board is updated correctly and that merges are handled without double merging. Test with various cases including no movement, single merge, multiple merges, and full board.
Discuss time complexity (O(n^2) for 4x4 board, effectively constant) and space complexity (O(1) if in-place, or O(n) for temporary arrays). Mention trade-offs between code clarity and performance.
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