I went for the rotation first, which was a mistake.
Clarify the problem constraints and edge cases first, then propose an efficient solution that simulates gravity column by column and rotates the grid in a single pass. Discuss time and space complexity, and consider whether in-place rotation is possible or if a new matrix is acceptable.
Pro tip: Mention that you can combine gravity and rotation by processing columns from bottom to top and writing directly into the rotated positions, avoiding an extra pass. This shows you think about optimizing beyond the naive approach.
Ask about grid dimensions, character representations, and whether rotation should be in-place. Confirm behavior for empty grids, all obstacles, or all stones.
For each column, iterate from bottom to top, keeping a pointer for the next available empty slot. Move stones down to the lowest available empty cell, skipping obstacles.
After gravity, rotate the grid 90 degrees clockwise. This can be done by creating a new matrix where new[i][j] = old[m-1-j][i], or in-place using transpose and reverse.
Instead of simulating gravity then rotating, process each column from bottom to top and directly place stones into the rotated matrix at the correct positions, reducing time and space overhead.
State time complexity O(m*n) and space complexity O(m*n) for the output (or O(1) extra if in-place). Walk through a small example to verify correctness.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.