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Meta·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
May 2026Remote

Summary

Meta SWE coding round, one grid traversal problem the whole session. Pretty standard stuff if you've done BFS before, but there are enough edge cases to trip you up if you're not careful.

Questions Asked (1)

Q1

Given a 2D grid with walls, open cells, a start, and an end, find the shortest path between start and end using 4-directional movement. Return the path length and reconstruct the path if possible.

Algorithms & Data Structures
Author's notes

BFS is the obvious move here and I got there pretty fast.

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AI HintsAI Generated

Suggested Approach

Use BFS to find the shortest path in an unweighted grid, tracking parent pointers to reconstruct the path. Start by clarifying the problem constraints, then explain the BFS algorithm, and finally discuss path reconstruction and complexity.

Pro tip: Mention that BFS is optimal for unweighted grids and that using a queue ensures the first time you reach the end is the shortest path. Also, discuss how to handle edge cases like no path or start equals end.

1. Clarify the problem

Ask about grid dimensions, movement rules, and whether diagonal moves are allowed. Confirm that the grid is unweighted and that you need the shortest path length and the actual path.

2. Choose BFS

Explain that BFS is ideal for finding the shortest path in an unweighted graph. Mention that each cell is a node, and edges connect adjacent open cells.

3. Implement BFS with parent tracking

Use a queue to explore level by level, marking visited cells. Store the parent of each visited cell to reconstruct the path later.

4. Reconstruct the path

Once the end is reached, backtrack from the end to the start using the parent pointers to build the path. If the queue empties without reaching the end, return no path.

5. Analyze complexity

State that time complexity is O(R*C) where R and C are grid dimensions, and space complexity is O(R*C) for the queue and visited set.

Key Points to Mention

  • BFS guarantees shortest path in unweighted graphs
  • Use a queue for level-order traversal
  • Track parent pointers to reconstruct the path
  • Handle edge cases: start equals end, no path exists
  • Time and space complexity: O(R*C)
  • Avoid revisiting cells by marking visited

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.