The triangle inequality part is straightforward once you remember you need all three checks, not just one.
Clarify the problem and edge cases, then propose an O(n) solution that checks each consecutive triple using the triangle inequality. Emphasize that for positive integers, only the sum of the two smaller sides needs to exceed the largest side, which simplifies the check.
Pro tip: Mention that since the array is positive, you can avoid sorting each triple by just checking if the sum of the two smaller elements (min and mid) is greater than the max. This shows optimization awareness and mathematical insight.
Confirm that the output length is n-2, each element corresponds to a triple starting at index i (0 ≤ i ≤ n-3), and that a valid triangle requires the sum of any two sides to be greater than the third.
For positive integers, the triangle inequality reduces to checking if the sum of the two smaller sides is greater than the largest side. This avoids checking all three inequalities.
Iterate through the array from index 0 to n-3. For each triple, find the min, mid, and max values (or sort the triple) and check if min + mid > max. Append 1 if true, else 0.
The algorithm runs in O(n) time with O(n) space for the output (or O(1) extra space if output is not counted). Sorting each triple would be O(n log 3) = O(n) but with higher constant; direct comparison is better.
If n < 3, return an empty array. Also consider large integers and potential overflow (though Python handles big ints natively).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.