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Squarepoint·Data Scientist·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
May 2026

Summary

Squarepoint Data Scientist interview with a coding round that leaned more algorithmic than I expected for the role. The stock prices problem came up in two parts and they wanted both solutions plus complexity analysis on the spot.

Questions Asked (2)

Q1

Given an array of daily stock prices, find the maximum profit from a single buy-sell transaction. You must buy before you sell and cannot short. Return 0 if no profit is possible.

Algorithms & Data Structures
Author's notes

The single-transaction version I got pretty quickly.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints (single transaction, buy before sell, return 0 if no profit) and then walk through a one-pass solution that tracks the minimum price seen so far and the maximum profit. Explain the time and space complexity, and mention edge cases like decreasing prices or empty array.

Pro tip: Emphasize that this is a classic 'buy low, sell high' problem where you only need to remember the lowest price so far, not the entire history. Mentioning that the algorithm runs in O(n) time and O(1) space demonstrates you understand the optimal solution.

1. Clarify the problem

Confirm that only one buy and one sell are allowed, the buy must occur before the sell, and that no profit means returning 0. Ask about edge cases like empty array or single element.

2. Outline a brute-force approach

Briefly mention that a nested loop checking all pairs would be O(n^2), but it's not optimal. This shows you can start simple and then improve.

3. Describe the optimal one-pass algorithm

Initialize min_price to infinity and max_profit to 0. Iterate through prices, update min_price if current price is lower, else update max_profit if current price minus min_price is greater than max_profit.

4. Analyze complexity and edge cases

State that the algorithm runs in O(n) time and O(1) space. Discuss edge cases: empty array returns 0, decreasing prices return 0, and single element returns 0.

5. Provide a code example or pseudocode

Write clear pseudocode or a concise implementation in a language like Python to demonstrate the solution.

Key Points to Mention

  • Time complexity: O(n) single pass
  • Space complexity: O(1) constant extra space
  • Tracking minimum price seen so far
  • Updating maximum profit when a higher selling price is found
  • Handling edge cases: empty array, single element, strictly decreasing prices
  • Returning 0 when no profit is possible

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Now extend it: you can make as many buy-sell transactions as you want, but you can only hold one share at a time. What is the maximum total profit, and what is the complexity of your solution?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This part tripped me up for a moment because I started thinking about DP tables before realizing the greedy insight is almost embarrassingly simple.

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AI HintsAI Generated

Suggested Approach

Recognize this as the classic 'Best Time to Buy and Sell Stock II' problem where unlimited transactions are allowed. The optimal strategy is to sum all positive daily price differences, which is equivalent to capturing every upward movement. This yields an O(n) time and O(1) space solution.

Pro tip: Emphasize that the greedy approach works because any profitable trade can be decomposed into a series of consecutive daily gains, and holding through a dip would only reduce profit. Also, mention that this assumes no transaction costs; if costs exist, the problem becomes more complex.

1. Clarify the problem

Confirm that you can buy and sell multiple times but must sell before buying again, and that you start with no stock. Ask if there are any transaction fees or constraints.

2. Identify the greedy insight

Realize that to maximize profit, you should buy before every price increase and sell before every decrease. This is equivalent to summing all positive differences between consecutive days.

3. Prove optimality

Explain that any optimal solution can be transformed into this greedy one without reducing profit, because each profitable trade can be broken into daily gains, and skipping a positive day would lose profit.

4. Implement and analyze

Write a simple loop that iterates through the price array, adding max(0, prices[i] - prices[i-1]) to the total profit. State that time complexity is O(n) and space is O(1).

5. Discuss extensions

Mention variations like transaction fees, cooldown periods, or limited transactions, and how they would change the approach (e.g., dynamic programming).

Key Points to Mention

  • Greedy algorithm: sum all positive price differences.
  • Time complexity O(n) and space complexity O(1).
  • Proof of optimality: any profitable trade can be decomposed into consecutive daily gains.
  • Assumption of no transaction costs; if costs exist, the greedy approach may not be optimal.
  • Comparison to the single-transaction version (track min price and max profit).
  • Edge cases: empty array, decreasing prices, single element.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.