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Amazon·Software Engineer·Technical Phone Screen·Senior

SeniorPrefer not to say
May 2026

Summary

Amazon SWE interview that went deep on a classic string segmentation problem. They didn't just want a working solution, they kept pushing on tradeoffs and edge cases until I ran out of clever things to say.

Questions Asked (4)

Q1

Given a string and a dictionary of words, can the string be broken into a valid sequence of dictionary words? Walk through a dynamic programming solution.

Algorithms & Data Structures
Author's notes

I jumped straight to the DP table without talking through examples first, which I think annoyed the interviewer a bit.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints (e.g., can words be reused? empty string? case sensitivity?) and then explain the dynamic programming approach where dp[i] indicates whether the substring s[0..i-1] can be segmented. Walk through the recurrence dp[i] = OR over j < i of (dp[j] AND s[j..i-1] in dictionary), and discuss time/space complexity and possible optimizations.

Pro tip: Mention that you can optimize by only checking j values where dp[j] is true and by limiting j to the maximum word length in the dictionary, reducing unnecessary checks. Also, consider using a trie for faster dictionary lookups if the dictionary is large.

1. Clarify the problem and edge cases

Ask about constraints: can words be reused? Is the dictionary a set or list? Are there empty strings? This ensures you understand the problem fully before diving into the solution.

2. Define the DP state and recurrence

Let dp[i] be true if the prefix s[0..i-1] can be segmented. Then dp[i] is true if there exists j < i such that dp[j] is true and s[j..i-1] is in the dictionary. Base case: dp[0] = true.

3. Walk through an example

Illustrate with a small example, e.g., s = 'leetcode', dict = ['leet', 'code'], showing how dp array is filled step by step.

4. Analyze complexity and optimizations

Time complexity is O(n^2) in the worst case (or O(n * maxWordLen) with optimization), space O(n). Mention using a set for O(1) lookups and possibly a trie for large dictionaries.

5. Discuss alternative approaches and trade-offs

Mention BFS/DFS with memoization as an alternative, and compare trade-offs. Also, note that the DP approach is bottom-up and avoids recursion overhead.

Key Points to Mention

  • DP state definition: dp[i] represents whether prefix s[0..i-1] can be segmented.
  • Recurrence relation: dp[i] = OR_{j < i} (dp[j] AND s[j..i-1] in dict).
  • Base case: dp[0] = true (empty string).
  • Time complexity: O(n^2) naive, O(n * maxWordLen) optimized; space O(n).
  • Use a set for O(1) dictionary lookups; consider trie for large dictionaries.
  • Edge cases: empty string, no valid segmentation, words can be reused (unless specified otherwise).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

How would you redesign the solution using a Trie to speed up prefix lookups and allow early termination on long inputs?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where it got interesting and also where I got a little shaky.

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AI HintsAI Generated

Suggested Approach

Start by explaining the current solution's bottleneck in prefix lookups, then describe how a Trie (prefix tree) can reduce lookup time to O(L) where L is the prefix length. Emphasize early termination by stopping traversal when the prefix is exhausted or a null child is encountered, and discuss trade-offs like memory overhead and implementation complexity.

Pro tip: Quantify the improvement: compare the current O(N) or O(log N) lookup with Trie's O(L) and highlight that early termination is especially beneficial for long inputs where the prefix diverges early. Also mention that Amazon values customer obsession, so tie the optimization to faster response times for end users.

1. Identify the bottleneck

Explain why the current solution is slow for prefix lookups, e.g., scanning a list or binary search on sorted strings, and quantify the time complexity.

2. Introduce Trie structure

Describe how a Trie stores characters as nodes, with each node representing a prefix, and how this enables O(L) lookup for a prefix of length L.

3. Enable early termination

Explain that during traversal, if a character is not found or the prefix ends, you can immediately return false or the result, avoiding unnecessary work.

4. Discuss trade-offs

Acknowledge memory overhead (each node may have many children) and potential solutions like compressed tries or ternary search trees, and compare with alternative data structures.

5. Conclude with impact

Summarize how this redesign speeds up prefix lookups, especially for long inputs, and aligns with Amazon's leadership principles like customer obsession and invent & simplify.

Key Points to Mention

  • Time complexity: O(L) for lookup vs O(N) or O(log N) in current solution
  • Space complexity: O(total characters * alphabet size) and mitigation strategies
  • Early termination: stop traversal when prefix ends or mismatch occurs
  • Use cases: autocomplete, spell check, IP routing
  • Trade-offs: memory vs speed, implementation complexity
  • Amazon leadership principles: customer obsession, invent & simplify

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

What are the time and space complexity tradeoffs between the basic DP approach and the Trie-based approach?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Blanked for a second on how to articulate the memory overhead of the Trie clearly.

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AI HintsAI Generated

Suggested Approach

Start by clearly defining the problem context (e.g., word break or string matching) and then compare the time and space complexities of the basic DP and Trie-based approaches. Explain how the Trie optimizes the inner loop by reducing redundant substring checks, and discuss the tradeoff of increased space due to the Trie structure.

Pro tip: Tie the tradeoff to Amazon's leadership principles: emphasize that the Trie approach often reduces time complexity at the cost of space, which aligns with 'Customer Obsession' by improving performance for large inputs, but also mention that you'd consider memory constraints in production systems.

1. Clarify the problem and assumptions

Restate the problem (e.g., word break) and specify the input sizes and constraints. Mention that the basic DP approach typically has O(n^2) time and O(n) space, while the Trie-based approach can achieve O(n * m) time where m is the average word length, with O(total characters) space for the Trie.

2. Analyze the basic DP approach

Explain that DP checks all possible substrings, leading to O(n^2) time in the worst case (or O(n * L) where L is max word length) and O(n) space for the DP array. Note that it may re-scan the same substrings repeatedly.

3. Analyze the Trie-based approach

Describe how building a Trie of the dictionary allows for efficient prefix matching. The time complexity becomes O(n * m) where m is the maximum word length, as each starting position traverses the Trie up to m characters. Space is O(total characters in dictionary) for the Trie plus O(n) for DP.

4. Compare and contrast tradeoffs

Highlight that the Trie reduces time by avoiding redundant substring checks, but increases space due to the Trie structure. Discuss scenarios where each is preferable: DP for small dictionaries or memory-constrained environments, Trie for large dictionaries or when many repeated prefix checks occur.

5. Conclude with practical implications

Summarize that the choice depends on the specific constraints: if memory is abundant and time is critical, Trie is better; if memory is tight, DP may suffice. Mention that in practice, optimizations like using a set for dictionary lookups can also affect the tradeoff.

Key Points to Mention

  • Time complexity of basic DP: O(n^2) or O(n * L) where L is max word length, due to checking all substrings.
  • Space complexity of basic DP: O(n) for the DP array.
  • Time complexity of Trie-based approach: O(n * m) where m is max word length, as each position traverses the Trie.
  • Space complexity of Trie: O(total characters in dictionary) plus O(n) for DP.
  • Tradeoff: Trie reduces time by eliminating redundant substring checks but increases space.
  • Practical considerations: dictionary size, memory constraints, and whether the problem involves multiple queries.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

How would you modify the solution to return one valid segmentation, or all possible segmentations?

Algorithms & Data Structures
Author's notes

Returning one segmentation is just backtracking through the DP table once you've filled it.

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AI HintsAI Generated

Suggested Approach

First, clarify the original problem (likely word break or palindrome partitioning) and the current solution's output. Then, explain how to modify the DP to reconstruct one solution by storing backpointers, and how to extend it to enumerate all solutions using backtracking or DFS with memoization. Emphasize trade-offs in time and space complexity.

Pro tip: Mention that returning all segmentations can be exponential in output size, so it's crucial to discuss output-sensitive complexity and potential memory optimizations like lazy enumeration. Also, relate to Amazon's leadership principles by emphasizing customer obsession (delivering correct, efficient solutions) and dive deep (understanding trade-offs).

1. Clarify the problem and current solution

Restate the original problem (e.g., word break) and describe the existing DP solution that only returns a boolean. Confirm whether the interviewer wants one or all segmentations.

2. Modify DP to store reconstruction info

For one segmentation, augment the DP table to store the index of the previous cut (backpointer) when a valid segmentation is found. Then backtrack from the end to reconstruct the path.

3. Extend to all segmentations

Use DFS with memoization: at each position, try all valid next words and recursively build segmentations. Memoize results for each index to avoid recomputation, or use backtracking with pruning.

4. Analyze complexity and trade-offs

Discuss time and space complexity: for one segmentation O(n^2) time and O(n) space; for all, output-sensitive O(n * 2^n) worst-case, and memory can be high. Mention lazy enumeration if needed.

5. Handle edge cases and optimize

Consider empty string, no segmentation, and duplicate words. Optimize by using a set for dictionary lookups and pruning invalid paths early.

Key Points to Mention

  • Dynamic programming with backpointers for single solution reconstruction
  • DFS/backtracking with memoization for enumerating all solutions
  • Time and space complexity analysis, including output-sensitive complexity
  • Handling of edge cases (empty string, no solution, overlapping words)
  • Trade-offs between storing all solutions vs. lazy enumeration
  • Use of trie or set for efficient dictionary lookups

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.