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The second I saw 'visit all required nodes and return to start' I knew it was TSP-flavored but blanked on the exact DP formulation for a bit.
This is a variant of the Traveling Salesman Problem with optional intermediate nodes. The optimal strategy is to compute all-pairs shortest paths between the origin and required nodes, then solve the TSP on the reduced metric graph using dynamic programming (Held-Karp algorithm).
Pro tip: Mention that the problem is NP-hard, so for large inputs you'd need approximation or heuristic approaches, but for typical interview constraints the DP solution is expected. Also, clarify edge cases like unreachable required nodes.
Ask about graph size, whether edges are directed or undirected, if weights are non-negative, and if all required nodes are reachable. This shows attention to detail.
Compute shortest paths from origin to all required nodes and between all pairs of required nodes using Dijkstra's algorithm (or Floyd-Warshall for dense graphs). This creates a complete graph on the required nodes plus origin with metric distances.
Use bitmask DP where state is (current node, set of visited required nodes). Transition by adding an unvisited required node, and finally return to origin. This gives optimal tour in O(2^k * k^2) time where k is number of required nodes.
Discuss time and space complexity, and mention that for large k, approximation algorithms like Christofides or heuristics (nearest neighbor, 2-opt) may be needed.
Consider cases where a required node is unreachable, or when there are no required nodes (return 0). Also, if multiple required nodes are the same, deduplicate.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.