← Instacart Interview Insights
The simple cases like '3[a]2[bc]' are easy enough to reason through, but the nested version like '3[a2[c]]' is where I had to slow down and actually think about the stack structure.
Use a stack-based approach to handle nested patterns: iterate through the string, pushing characters and numbers onto a stack until a closing bracket is encountered, then pop and repeat the substring accordingly. Alternatively, use recursion to parse the string, treating each bracketed section as a recursive call. Both methods efficiently handle nesting and repetition.
Pro tip: Clarify edge cases upfront, such as multi-digit numbers, empty brackets, and invalid input, to demonstrate thoroughness. Also, discuss time and space complexity: O(n) time where n is the length of the decoded string, and O(m) space where m is the depth of nesting.
Ask about input format, character set, maximum nesting depth, and whether the input is guaranteed valid. Confirm expected output and edge cases like empty strings or numbers with multiple digits.
Decide between iterative stack-based parsing or recursive descent. Explain the trade-offs: stack avoids recursion depth limits, while recursion can be more intuitive for nested structures.
For stack: traverse the string, push characters and numbers onto a stack; on ']', pop until '[', then pop the number, repeat the substring, and push back. For recursion: parse until ']', building substrings and repeating when a number precedes '['.
Write clean code with helper functions if needed. Test with simple cases like '3[a]', nested cases like '3[a2[c]]', and edge cases like '10[ab]' or empty input.
Discuss time and space complexity. Consider optimizations like using a StringBuilder for efficient string concatenation or avoiding unnecessary string copies.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.