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Google·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Jun 2026

Summary

Google coding interview, grid traversal problem with a couple of follow-ups that went deeper than I expected. Pretty standard on the surface but the follow-ups are where they actually test you.

Questions Asked (3)

Q1

Given a 2D grid with possible obstacles, implement a shortest-path search from a start cell to a target cell using BFS. Alternatively, count the number of connected regions in the grid.

Algorithms & Data Structures
Author's notes

Got the BFS skeleton down pretty fast, 4-directional moves, visited set, queue.

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AI HintsAI Generated

Suggested Approach

Clarify the problem requirements and constraints, then choose BFS for shortest path or connected components based on the question. Implement the solution with careful handling of edge cases and analyze time/space complexity.

Pro tip: Demonstrate strong communication by discussing trade-offs between BFS and DFS, and mention how you would handle large grids or obstacles efficiently.

1. Clarify the problem

Ask questions to confirm grid dimensions, obstacle representation, movement directions (4 or 8), and whether start/target are guaranteed to be valid.

2. Choose the algorithm

For shortest path, use BFS with a queue; for connected regions, use BFS/DFS to explore each unvisited cell.

3. Outline the approach

Describe how you'll track visited cells, handle obstacles, and iterate through the grid or queue.

4. Analyze complexity

State time and space complexity: O(R*C) for both problems, with space O(R*C) for visited set or queue.

5. Discuss edge cases

Mention cases like empty grid, no path, start equals target, and large grids with many obstacles.

Key Points to Mention

  • BFS guarantees shortest path in unweighted graphs
  • Use a queue for BFS and a visited set to avoid cycles
  • For connected regions, iterate over all cells and BFS/DFS from unvisited non-obstacle cells
  • Time complexity is O(R*C) where R and C are grid dimensions
  • Space complexity is O(R*C) for visited set and queue
  • Handle obstacles by skipping them during traversal

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

How would you extend this to a 3D grid? Walk through the state representation and how complexity changes.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Wasn't expecting this pivot.

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AI HintsAI Generated

Suggested Approach

Start by generalizing the 2D state representation to 3D, explicitly defining coordinates and any additional state dimensions. Then analyze how each operation's complexity scales with the new dimension, using Big-O notation and considering trade-offs like memory vs. time. Conclude with potential optimizations or alternative approaches for 3D.

Pro tip: Demonstrate awareness that 3D problems often require balancing memory and time; mention techniques like sparse representations or dimensionality reduction when appropriate. Also, relate the extension to real-world applications (e.g., 3D pathfinding, volumetric data) to show practical insight.

1. Clarify the 2D baseline

Briefly restate the 2D problem, its state representation, and complexity to establish a clear foundation for extension.

2. Define 3D state representation

Specify how the state changes: add a z-coordinate, and consider if additional state variables (e.g., direction, visited flags) need expansion. Discuss data structures (e.g., 3D array, hash set of tuples).

3. Analyze complexity changes

Compare time and space complexity from 2D to 3D. For example, if 2D is O(n^2), 3D becomes O(n^3); if using BFS, the branching factor and queue size grow. Mention how constants and memory access patterns affect performance.

4. Discuss trade-offs and optimizations

Address challenges like increased memory usage and potential solutions: sparse data structures, pruning, bidirectional search, or heuristic improvements. Mention if the problem remains tractable or requires approximation.

5. Conclude with implications

Summarize the key changes and their impact on algorithm choice, emphasizing scalability and practical considerations for 3D grids.

Key Points to Mention

  • State representation: adding a third coordinate (x, y, z) and possibly extra dimensions like time or direction.
  • Complexity scaling: time and space often increase by a factor of n (e.g., O(n^2) to O(n^3)), but may be worse if branching factor grows.
  • Data structures: 3D arrays vs. hash maps for sparse grids; memory layout and cache efficiency.
  • Algorithm adaptations: BFS/DFS, A*, dynamic programming may need adjustments for 3D.
  • Optimization techniques: pruning, bidirectional search, sparse representations, or dimensionality reduction.
  • Real-world applications: 3D pathfinding, volumetric rendering, or robotics to contextualize the extension.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Why use BFS here instead of DFS or other search strategies? When would you prefer one over the other?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is the kind of question where you think you know the answer and then halfway through your explanation you realize you're not being precise enough.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem's structure and what property we need (e.g., shortest path, level-order, or exhaustive search). Then compare BFS and DFS based on their guarantees, complexity, and memory trade-offs, and explain when each is preferable with concrete examples.

Pro tip: Mention that BFS is optimal for unweighted shortest paths but can be memory-heavy, while DFS is better for space-constrained exhaustive searches; also note that for weighted graphs, Dijkstra or A* may be more appropriate.

1. Clarify the problem

Identify the graph type (unweighted/weighted, directed/undirected), the goal (shortest path, connectivity, cycle detection), and constraints (memory, time).

2. State BFS properties

Explain that BFS explores level by level, guaranteeing the shortest path in unweighted graphs, and uses a queue (O(V) memory in worst case).

3. State DFS properties

Explain that DFS explores deeply, uses a stack (O(V) memory but often less in practice), and is good for topological sorting, cycle detection, and path existence.

4. Compare trade-offs

Discuss time complexity (both O(V+E)), memory (BFS can be O(V) but often larger due to queue; DFS O(V) but can be less), and suitability for different graph shapes (e.g., BFS better for shallow graphs, DFS for deep).

5. Give when to prefer each

Conclude with scenarios: BFS for shortest path in unweighted graphs, level-order traversal, or finding nearest target; DFS for exhaustive search, topological sort, cycle detection, or when memory is tight.

Key Points to Mention

  • BFS guarantees shortest path in unweighted graphs; DFS does not.
  • BFS uses a queue and can have high memory usage (O(V) but often larger in practice); DFS uses a stack and can be more memory-efficient.
  • Time complexity for both is O(V+E) for adjacency list representation.
  • DFS is preferred for topological sorting, cycle detection, and path existence.
  • BFS is preferred for level-order traversal, finding connected components, and shortest path in unweighted graphs.
  • For weighted graphs, Dijkstra or A* may be better than BFS/DFS.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.