My first instinct was to just scan left to right and apply ops as I go, which breaks immediately once you account for operator precedence.
Use a single-pass stack-based algorithm: parse the string into tokens, then process multiplication and division immediately while pushing addition and subtraction results onto a stack. Finally, sum the stack to get the result. This handles operator precedence without parentheses and runs in O(n) time.
Pro tip: Mention that you can avoid a separate tokenization pass by parsing numbers and operators on the fly, and explicitly discuss how you handle division truncation toward zero for negative intermediate results (e.g., using truncation instead of floor).
Confirm input constraints: non-negative integers, operators + - * /, spaces, no parentheses, division truncates toward zero. Discuss handling of large numbers, empty strings, and potential overflow.
Select a stack-based approach to handle operator precedence: process * and / immediately, and push + and - terms onto a stack. Alternatively, use two stacks (operands and operators) but the single stack is simpler.
Iterate through the string, building numbers and tracking the last operator. When an operator is encountered, apply the previous operator to the current number and the top of the stack (for * and /) or push the number (for + and -). Handle spaces by skipping them.
Ensure division truncates toward zero. In languages like Python, use int(a / b) or math.trunc(a / b) instead of // (which floors). In Java/C++, integer division already truncates toward zero.
State time complexity O(n) and space complexity O(n) in the worst case (e.g., all additions). Walk through examples like '3+2*2', ' 3/2 ', and '3+5 / 2' to verify correctness.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.