I spent the first few minutes trying to think of a greedy ordering, like merge the branch with the fewest overlapping files first.
Model the problem as finding a permutation of branches that minimizes the total number of conflicting commits. Since n ≤ 15, use bitmask dynamic programming where the state is the set of already merged branches, and the DP value is the minimum conflicts so far. Precompute for each branch the set of files it touches and the number of commits that conflict with any given set of files.
Pro tip: Emphasize that the conflict count for a branch depends only on the union of files touched by previously merged branches, not on their order. This allows efficient precomputation and makes the DP state sufficient.
Clarify that conflicts are counted per commit, not per file, and that the first branch merged has zero conflicts. Note that n ≤ 15 suggests an exponential algorithm like bitmask DP.
For each branch, compute the set of files it touches. Also, for each branch, determine for every possible subset of files (or efficiently during DP) how many of its commits conflict with that subset.
Let dp[mask] = minimum conflicts after merging the branches in mask. For each branch not in mask, the additional conflicts are the number of commits in that branch that touch any file in the union of files from branches in mask. Transition to dp[mask | (1<<i)].
Precompute for each branch i and each mask the number of conflicting commits when merging i after the set mask. This can be done by iterating over commits and checking if any file is in the union of files of mask, or by using bitmask of files and precomputed commit masks.
After filling the DP table, the answer is dp[(1<<n)-1]. Discuss time complexity: O(2^n * n * C) where C is total commits, or O(2^n * n) with precomputation.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.