This one took me a while to get traction on.
Start by clarifying requirements and constraints, then propose a data structure like a balanced BST or segment tree to manage free blocks, explaining how allocate and free operations achieve O(log m) each. Discuss trade-offs between different approaches and how to handle edge cases like coalescing and fragmentation.
Pro tip: Emphasize that the O(m log m) bound is independent of n, so the solution must not iterate over the entire memory region; instead, use a data structure that scales with the number of operations. Also, mention that using a balanced BST keyed by address allows efficient leftmost-fit search and neighbor coalescing.
Confirm the interface, expected operation counts, and performance goals. Ask about alignment, thread safety, and whether memory can be over-allocated.
Select a data structure that supports efficient search, insertion, and deletion of free blocks, such as a balanced BST (e.g., red-black tree) keyed by block address, or a segment tree over the operation indices.
Find the leftmost free block with size >= requested size using the data structure. Split the block if larger, update the structure, and return the address.
Locate the block containing addr, mark it free, and coalesce with adjacent free blocks by checking neighbors via the data structure. Update the structure accordingly.
Show that each operation takes O(log m) time, leading to O(m log m) total. Discuss trade-offs: BST vs. segment tree, memory overhead, and handling fragmentation.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.