The no-heap constraint threw me for a second because my first instinct was literally a max-heap.
Clarify that this is the 0/1 knapsack problem where size is weight and fee is value, then implement a dynamic programming solution using a 2D table (or 1D array) to avoid heaps. Walk through the DP recurrence, initialization, and how to reconstruct the selected transactions.
Pro tip: Mention that while DP is optimal for small capacity (100), for large capacities a greedy approach by fee-to-size ratio is a common heuristic but not always optimal—showing you understand trade-offs.
Confirm that each transaction can be included at most once (0/1 knapsack) and that total size must not exceed 100. Ask if fees and sizes are integers and if negative values are possible.
Let dp[i][s] be the maximum fee using first i transactions with total size exactly s (or at most s). Recurrence: dp[i][s] = max(dp[i-1][s], dp[i-1][s - size_i] + fee_i) if size_i <= s.
Initialize dp[0][s] = 0 for all s (or -inf if exact size required). Iterate i from 1 to N, s from 0 to 100, filling the table. Use a 1D array for space optimization if needed.
Backtrack from dp[N][100] to determine which transactions were selected by checking if the value came from including the current item.
Time O(N * 100), space O(N * 100) or O(100) with 1D array. Discuss that this is pseudo-polynomial and works well for small capacity, but for large capacity other approaches (e.g., branch and bound) might be needed.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.
Recognize that the parent-child dependency forms a forest (or DAG) where selecting a child requires selecting all ancestors, so the problem becomes selecting a set of nodes closed under ancestors to maximize total fee. Propose a dynamic programming approach on the tree structure, computing for each node the optimal selection of its subtree given whether the node is selected or not, then combine children choices. Discuss trade-offs between exact DP and greedy heuristics for large graphs, and mention how to handle cycles or multiple parents if the dependency is a DAG.
Pro tip: Emphasize that this is essentially a tree knapsack or maximum weight closure problem, and mention that for large-scale systems you might use a greedy approximation with priority queues while maintaining ancestor closure, but always validate with a DP on smaller instances.
Explain that each transaction is a node, and parent dependencies form directed edges from child to parent. If each transaction has at most one parent, it's a forest; if multiple, it's a DAG. The goal is to select a subset of nodes closed under ancestors (if a node is selected, all its ancestors must be selected) to maximize sum of fees.
For a tree, define DP[v][0] = max fee in subtree of v when v is not selected (then no descendant can be selected because selecting a descendant requires v), so DP[v][0] = 0. DP[v][1] = fee(v) + sum over children c of max(DP[c][0], DP[c][1]). For a DAG, use topological order and propagate constraints, or transform to a tree by duplicating nodes if needed.
If a node has multiple parents, it can only be selected if all parents are selected. This is a maximum weight closure problem, solvable by min-cut. Mention that cycles (if any) must be contracted or handled by strongly connected components, as they force all-or-nothing selection.
Tree DP runs in O(n) time and space. For DAGs, min-cut on a graph with n nodes and m edges runs in polynomial time but may be too slow for very large n. Propose greedy heuristics: sort by fee, try to add transactions if all ancestors are already selected, using a priority queue and union-find to track availability.
For exact optimality on moderate sizes, use DP or min-cut. For real-time systems with millions of transactions, use a greedy approximation that respects dependencies, possibly with a threshold or budget. Mention that the greedy may not be optimal but is fast and often close.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.