The solution itself clicked pretty fast, sliding window with a running max frequency.
Use a sliding window (two-pointer) technique to maintain a window where the number of characters to replace (window length minus the count of the most frequent character) is at most k. Expand the right pointer, and when the condition is violated, shrink the window from the left. Track the maximum window length seen.
Pro tip: Emphasize that the window size never decreases, which allows O(n) time and O(1) space. Also, mention that this approach is optimal and can handle very large inputs efficiently.
Restate the problem in your own words and ask clarifying questions. Discuss edge cases like k=0, empty string, k >= string length, and very large inputs.
Explain that you'll maintain a window [left, right] and a frequency count of characters. The window is valid if (window length - max frequency) <= k. Expand right, and if invalid, move left.
Argue that the window always represents a valid substring, and since we only expand when possible, the maximum length is found. Time complexity O(n), space O(1) (since alphabet size is fixed).
For k=0, it reduces to finding the longest substring with all same characters. For very large inputs, the O(n) time and O(1) space make it efficient. Mention that the window size never decreases, so we can avoid shrinking below the current max.
Compare with brute force O(n^2) or binary search with sliding window. Highlight that the sliding window is optimal and simple to implement.
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