I started coding way too fast and got the left-scan logic backwards.
Clarify the water flow rules and edge cases, then design an efficient simulation. For each unit, find the nearest strictly lower position to the left; if none, find the nearest strictly lower position to the right; otherwise, keep it at K. Use a stack or precomputed arrays to avoid O(V*N) time.
Pro tip: Discuss trade-offs between simulation and precomputation, and mention that the problem can be solved in O(N) preprocessing and O(1) per drop using monotonic stacks or segment trees, which is crucial for large V.
Ask questions to confirm the flow rules: does water flow to the nearest strictly lower position? What if multiple lower positions exist? Confirm that water accumulates and changes heights, affecting subsequent drops.
For each water unit, scan left from K to find the first index with height < current height at K. If found, increment that height and update K to that index? Actually, the problem says 'flows left as far as possible to a strictly lower position', so it moves to the leftmost strictly lower position? Clarify: typically it means the nearest strictly lower position to the left. Then if blocked, try right. If neither, stay at K.
Precompute for each index the nearest strictly lower index to the left and right using monotonic stacks. Then each drop can be processed in O(1) by checking these precomputed indices, updating heights and possibly updating the precomputed arrays dynamically.
Since heights change after each drop, the precomputed nearest lower indices may become invalid. Consider using a balanced BST or segment tree to maintain the heights and query the nearest lower position efficiently.
Discuss time and space complexity. Test with edge cases: V=0, K at boundaries, all heights equal, strictly decreasing/increasing arrays.
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