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The BFS itself wasn't the hard part, I've done it a hundred times.
Start by clarifying the problem and edge cases, then walk through the BFS algorithm step-by-step, emphasizing initialization, queue operations, and neighbor traversal. Finally, analyze time and space complexity, and discuss how to reconstruct paths using the parent array.
Pro tip: Mention that BFS naturally handles disconnected graphs by leaving unreachable nodes at -1, and that the parent array can be used to reconstruct the shortest path by backtracking from the target to the source.
Confirm input format (adjacency list), output requirements (distance and parent arrays), and edge cases like disconnected graphs or source not in graph. Outline the BFS approach.
Create distance array filled with -1, parent array filled with -1, and a queue. Set distance[s] = 0 and enqueue s.
While queue is not empty, dequeue a vertex u. For each neighbor v of u, if distance[v] == -1, set distance[v] = distance[u] + 1, parent[v] = u, and enqueue v.
After BFS, return the distance and parent arrays. Unreachable nodes remain -1 in both arrays.
Time complexity: O(n + m) since each vertex and edge is processed once. Space complexity: O(n) for distance, parent, and queue.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.