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Meta·Software Engineer·Technical Phone Screen·Senior

SeniorPrefer not to say
Jul 2026

Summary

Meta Research Engineer AI round, just one coding problem but it was trickier than it looked on the surface.

Questions Asked (1)

Q1

Given a list of words, find the subset of words that have the most unique characters, where no word in the subset contains any duplicate characters.

Algorithms & Data Structures
Author's notes

Spent the first few minutes just making sure I understood what 'no duplicate characters' meant for individual words versus across the subset.

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AI HintsAI Generated

Suggested Approach

Use bitmask representation to encode each word's unique character set as an integer, then apply a greedy or backtracking search to find the subset of non-overlapping bitmasks whose combined bit count is maximized. This approach leverages bitwise AND to quickly check for character conflicts and bitwise OR to accumulate the union of characters. Start by filtering out words with duplicate characters, since they can never contribute to a valid subset.

Pro tip: Mention that pre-filtering words with duplicate characters and deduplicating bitmasks (multiple words can share the same character set) significantly prunes the search space — this shows awareness of practical optimization beyond the naive solution, which Meta interviewers value highly.

1. Clarify & Understand the Problem

Confirm that 'no word contains duplicate characters' means each word in the chosen subset must itself have all unique letters, and that no two words in the subset share any character. Ask about constraints like word length, alphabet size, and list size to gauge expected complexity.

2. Filter & Encode Words as Bitmasks

Discard any word that contains a repeated character (detectable in O(n) per word). For each remaining word, encode its character set as a 26-bit integer where bit i is set if the i-th letter of the alphabet is present, enabling O(1) conflict checks via bitwise AND.

3. Deduplicate Bitmasks

Multiple words may map to the same bitmask; keep only unique bitmasks since choosing any one representative is equivalent. This reduces the effective search space and avoids redundant computation during the subset search.

4. Backtracking Search Over Bitmasks

Use a recursive backtracking approach: iterate over bitmasks, and for each candidate, check if it conflicts with the current accumulated bitmask (AND == 0). If not, OR it in and recurse, tracking the maximum popcount (total unique characters) seen across all valid subsets.

5. Analyze Complexity & Discuss Trade-offs

The worst-case is O(2^N) over filtered bitmasks, but in practice the alphabet constraint (26 bits) and early pruning make it tractable. Discuss potential optimizations such as sorting bitmasks by popcount descending for better pruning, or using memoization on the accumulated bitmask state.

Key Points to Mention

  • Bitmask representation of character sets enables O(1) conflict detection using bitwise AND and efficient union via bitwise OR
  • Pre-filtering words with duplicate characters is a necessary first step since they violate the problem constraint by definition
  • Deduplicating identical bitmasks reduces the search space without affecting correctness
  • Backtracking with pruning is the core algorithmic technique, and the 26-character alphabet naturally bounds the bitmask space
  • popcount (bit count) of the accumulated bitmask represents the total unique characters in the current subset, which is the value to maximize
  • Sorting candidates by popcount in descending order enables earlier pruning of branches that cannot beat the current best

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.