← Meta Interview Insights

Meta·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

Interviewed for a software engineer role at Meta, mostly coding-focused. The problems ranged from classic sliding window stuff to some trickier string manipulation questions that felt a bit obscure. Mixed bag overall.

Questions Asked (5)

Q1

Implement a moving average from a data stream, given a fixed window size.

Algorithms & Data Structures
Author's notes

Pretty standard sliding window with a queue.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Start by clarifying the problem: moving average of a data stream with a fixed window size. Then design a class that maintains a queue of the last N elements and a running sum, updating the average in O(1) time per element. Discuss edge cases like window not full and integer overflow.

Pro tip: Mention that you can optimize memory by using a circular buffer instead of a queue, and that the running sum approach avoids O(N) recomputation. Also, discuss thread-safety if the stream is concurrent.

1. Clarify requirements

Ask about window size, data types (int/double), and whether the stream is continuous. Confirm expected time complexity for each operation.

2. Design data structures

Choose a queue (or circular buffer) to store the window elements and a variable to keep the running sum. This allows O(1) updates.

3. Implement methods

Write a constructor to initialize window size, and a next(val) method that adds the new value, removes the oldest if window is full, updates sum, and returns the average.

4. Handle edge cases

Consider when the window is not yet full, division by zero, and potential integer overflow. Use double for sum and average.

5. Analyze complexity

State that each next() call is O(1) time and O(window size) space. Discuss trade-offs with alternative approaches like recomputing sum.

Key Points to Mention

  • Use a queue or circular buffer to maintain the window efficiently.
  • Keep a running sum to achieve O(1) time per operation.
  • Handle the case when the window is not yet full (average over fewer elements).
  • Use double for the sum and average to avoid integer division and overflow.
  • Discuss space complexity: O(window size) for storing elements.
  • Mention potential thread-safety if the stream is accessed concurrently.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Group a list of strings such that strings that are shifts of each other end up in the same group.

Algorithms & Data Structures
Author's notes

This one tripped me up more than I expected.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Clarify that a shift means a cyclic rotation, then use a canonical representation such as the lexicographically smallest rotation or a doubled-string substring to group equivalent strings. Hash each canonical form to a list of original strings, and discuss time/space complexity and edge cases.

Pro tip: Mention that you can compute the canonical form in O(n) using Booth's algorithm, but for interviews, the doubled-string approach with substring search is often sufficient and easier to explain. Also, handle empty strings and duplicates gracefully.

1. Clarify the problem

Confirm that 'shift' means cyclic rotation (e.g., 'abc' shifts to 'bca', 'cab') and that grouping should include all strings that are rotations of each other. Ask about input size, character set, and whether duplicates should be preserved.

2. Choose a canonical representation

For each string, compute a canonical key that is identical for all its rotations. Options: lexicographically smallest rotation (using Booth's algorithm in O(n)), or the smallest substring of length n in s+s (using KMP or similar).

3. Group using a hash map

Iterate through the list, compute the canonical key for each string, and append the original string to a list in a hash map keyed by the canonical form. This groups all rotations together.

4. Analyze complexity and edge cases

Discuss time complexity: O(N * L) where N is number of strings and L is average length, assuming O(L) canonicalization. Space: O(N * L) for the map. Handle edge cases: empty strings, single-character strings, strings with repeated characters, and duplicate strings.

5. Test and optimize

Walk through a small example to verify correctness. If needed, optimize canonicalization (e.g., Booth's algorithm) or consider alternative approaches like sorting each string's rotations.

Key Points to Mention

  • Definition of shift as cyclic rotation
  • Canonical representation: lexicographically smallest rotation or doubled-string substring
  • Hash map for grouping by canonical key
  • Time complexity: O(N * L) with efficient canonicalization
  • Edge cases: empty strings, duplicates, single characters
  • Alternative: Booth's algorithm for O(L) canonicalization

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Given a sorted integer array and a range, return all the missing ranges within that range.

Algorithms & Data Structures
Author's notes

Felt straightforward but there are a bunch of edge cases around the boundaries that'll get you if you're not careful.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Use a single pass through the sorted array, tracking the next expected number in the range. When a gap is found between the current expected number and the current array element, add the missing range, then update the expected number to the current element + 1. After the loop, check for any remaining gap up to the upper bound.

Pro tip: Clarify edge cases upfront: whether the range is inclusive, how to handle duplicates, and what to return if no missing ranges exist. This shows attention to detail and prevents incorrect assumptions.

1. Clarify the problem

Confirm the range bounds (inclusive/exclusive), input constraints (sorted, possible duplicates), and expected output format (e.g., list of strings like 'a->b' or 'a').

2. Initialize variables

Set a variable `next` to the lower bound of the range. This represents the next number that should be present in the array.

3. Iterate through the array

For each number `num` in the array, if `num > next`, add the missing range from `next` to `num-1`. Then update `next` to `num + 1` (skip duplicates by only updating if `num >= next`).

4. Handle the final gap

After the loop, if `next <= upper`, add the missing range from `next` to `upper`.

5. Format and return

Convert each missing range to the required string format (e.g., 'a->b' if a != b, else 'a') and return the list.

Key Points to Mention

  • Time complexity: O(n) where n is the length of the array, as we traverse it once.
  • Space complexity: O(1) extra space excluding the output list.
  • Handling duplicates: skip them by ensuring `next` is only updated when `num >= next`.
  • Edge cases: empty array, no missing ranges, range bounds outside array values.
  • Inclusive range: ensure the upper bound is included in the final check.
  • String formatting: use '->' for ranges with more than one number, otherwise just the number.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

Remove duplicate characters from a string while preserving the original order of first appearances.

Algorithms & Data Structures
Author's notes

Classic seen-set plus output buffer.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Clarify the problem constraints (e.g., character set, case sensitivity, in-place vs. new string) and then propose an efficient solution using a hash set to track seen characters while building the result. Walk through the algorithm with a simple example, analyze time and space complexity, and discuss potential optimizations or trade-offs.

Pro tip: Mention that for ASCII strings, a boolean array of size 128 can replace the hash set for O(1) lookups with lower constant factors, showing awareness of practical performance. Also, discuss how to handle Unicode characters if the interviewer raises that possibility.

1. Clarify requirements and constraints

Ask about the character set (ASCII vs. Unicode), case sensitivity, whether the input can be modified in-place, and expected output format. This ensures you solve the correct problem.

2. Choose data structures

Select a hash set to track seen characters for O(1) average lookup, or a boolean array for ASCII to optimize space and speed. Consider if additional data structures like a StringBuilder are needed for efficient string construction.

3. Design the algorithm

Iterate through the string, and for each character, check if it has been seen. If not, append it to the result and mark it as seen. This preserves the order of first appearances.

4. Analyze complexity and edge cases

State time complexity O(n) and space complexity O(k) where k is the number of unique characters. Discuss edge cases: empty string, all duplicates, no duplicates, and Unicode characters.

5. Test and optimize

Walk through a test case to verify correctness. If needed, discuss in-place modification for character arrays to save space, or using bit manipulation for lowercase letters.

Key Points to Mention

  • Time and space complexity analysis: O(n) time, O(k) space where k is unique characters.
  • Choice of data structure: hash set vs. boolean array (for ASCII) and their trade-offs.
  • Preservation of order: using an ordered approach like iterating and appending to a result.
  • Edge cases: empty string, all duplicates, no duplicates, case sensitivity, Unicode.
  • In-place modification possibility if input is a mutable character array.
  • Alternative approaches: using sorting (but that changes order) or bit manipulation for limited character sets.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q5

Given an array, return its elements in sorted order while maintaining stability and minimizing time/space complexity.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Vague framing on this one.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Clarify the definition of stability and the constraints (e.g., input size, data types, memory limits) before proposing a solution. Then discuss the trade-offs between comparison-based sorts (e.g., merge sort for stability) and non-comparison sorts (e.g., counting sort for integers), and justify your choice based on time/space complexity. Finally, outline the algorithm and analyze its complexity.

Pro tip: Mention that in practice, many standard library sorts (like Python's Timsort or Java's TimSort) are stable and optimized, so you'd likely use them unless there's a specific reason to implement your own. This shows awareness of real-world engineering.

1. Clarify requirements and constraints

Ask about input size, data types, memory limits, and what 'stability' means in this context (e.g., preserving relative order of equal elements). Confirm if the array can be modified in-place.

2. Discuss possible approaches

Compare stable sorting algorithms (merge sort, insertion sort, bubble sort) and non-comparison sorts (counting sort, radix sort) if applicable. Consider built-in stable sorts.

3. Analyze time and space complexity

For each candidate, state average/worst-case time and space complexity. Highlight that merge sort is O(n log n) time and O(n) space, while in-place sorts like insertion sort are O(n^2) time but O(1) space.

4. Select and justify the optimal solution

Choose the algorithm that best balances stability, time, and space based on constraints. For general case, merge sort or Timsort is often optimal; for small arrays, insertion sort may be efficient.

5. Outline implementation and edge cases

Describe the algorithm steps, handle edge cases (empty array, single element, duplicates), and mention potential optimizations (e.g., using insertion sort for small subarrays in merge sort).

Key Points to Mention

  • Definition of stability: equal elements retain their original relative order.
  • Merge sort is stable and guarantees O(n log n) time, but uses O(n) extra space.
  • In-place sorts like quicksort and heapsort are not stable; insertion sort is stable but O(n^2).
  • Non-comparison sorts (counting, radix) can be stable and faster for integers with limited range, but may use extra space.
  • Built-in language sorts (e.g., Python's sorted, Java's Arrays.sort for objects) are often stable and optimized.
  • Trade-offs: time vs. space, stability vs. in-place, and practical constraints like memory availability.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.