My first instinct was union-find, which was right, but I went straight to checking every pair and the interviewer let me code it up before pointing out the scale.
Model the balls as nodes in a graph where edges connect balls sharing a row or column within distance d. The minimum number of triggers equals the number of connected components in this graph, so the problem reduces to efficiently building the graph and counting components.
Pro tip: Avoid O(n^2) pairwise comparisons by sorting balls by row and column and only connecting adjacent balls within distance d; this reduces the graph construction to O(n log n) and shows you care about scalability.
Confirm the connection rules and that triggering a ball collects its entire connected component. Restate that the answer is the number of connected components.
Treat each ball as a node. Add edges between balls that share a row or column and are within distance d along that axis.
Group balls by row and by column. Within each group, sort by coordinate and connect consecutive balls if their difference ≤ d. This captures all necessary edges without O(n^2) comparisons.
Use Union-Find (Disjoint Set Union) or BFS/DFS to count the number of connected components. The count is the minimum number of triggers.
Discuss time and space complexity. Mention that the sorting-based approach is O(n log n) and that Union-Find with path compression and union by rank is efficient. Consider edge cases like duplicate coordinates or isolated balls.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.