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Meta·Machine Learning Engineer·Technical Phone Screen·Senior

Senior
Jun 2026

Summary

Meta ML Engineer interview with a debugging-focused coding round. The question looked approachable until I realized how much nuance they wanted out of a 'simple' BFS fix.

Questions Asked (1)

Q1

You're given a BFS implementation that loops infinitely on certain inputs. Find the bug and fix it, then explain your fix and its implications for correctness and complexity.

Algorithms & Data StructuresTechnical Trade-offsRoot Cause Analysis
Author's notes

The bug was pretty obvious once I saw it, no visited tracking anywhere.

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AI HintsAI Generated

Suggested Approach

First, clarify the BFS implementation and the specific inputs causing infinite loops. Then, systematically trace the algorithm to identify the bug, likely a missing visited set or incorrect queue management. Finally, propose a fix, analyze its impact on correctness and complexity, and discuss potential edge cases.

Pro tip: Emphasize the importance of a visited set to prevent revisiting nodes, and relate it to real-world ML scenarios like graph traversal in recommendation systems. Show that you consider both time and space complexity trade-offs.

1. Understand the BFS implementation

Ask clarifying questions about the code, such as whether it uses a queue, how nodes are marked as visited, and what inputs cause the infinite loop. Restate the problem to ensure alignment.

2. Identify the bug

Trace the algorithm on a simple cyclic graph to see if nodes are revisited. The bug is likely the absence of a visited set or incorrect placement of the visited check, causing infinite loops in graphs with cycles.

3. Propose a fix

Add a visited set to track enqueued nodes, and check before enqueueing neighbors. Ensure the check is done at enqueue time, not dequeue time, to prevent duplicates in the queue.

4. Analyze correctness and complexity

Explain that the fix ensures each node is processed once, making BFS terminate correctly. Time complexity remains O(V+E) but space complexity increases to O(V) for the visited set, which is standard for BFS.

5. Discuss implications and edge cases

Mention that without the visited set, BFS could loop indefinitely on cyclic graphs. Also, consider directed vs undirected graphs, disconnected components, and how the fix handles them.

Key Points to Mention

  • The necessity of a visited set to avoid infinite loops in cyclic graphs.
  • Correct placement of the visited check (at enqueue time) to prevent duplicate queue entries.
  • Time complexity O(V+E) and space complexity O(V) for BFS with visited set.
  • Impact on correctness: ensures termination and correct traversal order.
  • Edge cases: disconnected graphs, self-loops, and directed vs undirected graphs.
  • Potential trade-offs: using a set vs boolean array for visited tracking.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.