Spent the first few minutes just re-reading the problem because I kept thinking it was a shortest-path thing.
Model the problem as a deterministic finite automaton where the robot's state is its unknown position, and the instruction sequence must synchronize all possible states to the exit. Use a BFS over the product of all possible positions to find a sequence that drives every position to the exit, leveraging the fact that moves are deterministic and walls cause the robot to stay put.
Pro tip: Emphasize that the sequence must be universal—it works regardless of the starting cell—and discuss how the 'stay put' rule on walls can be exploited to simplify the synchronization process, showing you understand the practical constraints of real-world robotics.
Restate the problem: find a fixed sequence of moves that guarantees the robot reaches the exit from any starting position. Confirm that the robot has no sensors and that moves into walls or out of bounds result in no movement.
Represent the maze as a graph where each cell is a state. The instruction sequence must synchronize all states to the exit state. This is equivalent to finding a synchronizing word for a deterministic finite automaton where the exit is an absorbing state.
Use BFS on the set of possible positions (initially all non-wall cells) to find a sequence that reduces the set to just the exit. At each step, try all four moves and update the set of positions; if a move leads to a smaller set, continue. This is a shortest path in the power set automaton.
Discuss the worst-case complexity: the state space is 2^(number of cells), which is exponential. For small mazes, it's feasible; for large ones, heuristics or approximations may be needed. Mention that the problem is PSPACE-hard in general.
Relate to real-world robotics: such sequences are useful for calibration or recovery when localization fails. Discuss potential optimizations like exploiting symmetry or using a precomputed policy.
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