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Confluent·Software Engineer·Technical Phone Screen·Senior

Senior
Jul 2026

Summary

Confluent SWE interview with a graph traversal problem that had two parts, both harder than I expected. The second part especially had me scrambling to think through state space and complexity constraints on the fly.

Questions Asked (2)

Q1

You have a directed graph of n rooms, each with a monster that costs hp[i] energy to pass. Starting at room s with energy E, can you reach room t without your energy going negative? Return true/false and a valid path if one exists. Implement with DFS and pruning, and justify correctness and complexity.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Part A felt manageable once I framed it as a constrained path search.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and edge cases, then propose a DFS with pruning that tracks the maximum remaining energy at each visited node to avoid redundant exploration. Implement the solution, and finally justify correctness and analyze time and space complexity.

Pro tip: Mention that pruning by maximum energy per node is crucial for efficiency, and that the problem is NP-hard in general, so the DFS with pruning is a practical heuristic that works well for many cases but may still be exponential in the worst case.

1. Clarify and Define

Ask clarifying questions about graph size, energy bounds, and whether the path must be simple. Define the problem formally: find a path from s to t such that the cumulative sum of hp along the path never exceeds E.

2. Design the Algorithm

Propose a DFS that explores paths, but prune when the current energy is negative or when reaching a node with energy less than or equal to the maximum energy previously seen at that node. Use a hash map to store the best energy per node.

3. Implement and Test

Write clean code for the DFS with pruning, including path reconstruction. Walk through a small example to verify correctness, and discuss edge cases like s == t or no path.

4. Justify Correctness

Explain that the DFS explores all viable paths, and pruning is safe because if a node is reached with less energy than before, any continuation from that state is dominated by the previous visit. Thus, if a path exists, it will be found.

5. Analyze Complexity

State that the worst-case time complexity is O(n * E) or O(n^2) depending on pruning effectiveness, but in the worst case it can be exponential. Space complexity is O(n) for recursion stack and visited map.

Key Points to Mention

  • Pruning condition: only continue DFS if current energy > best_energy[node] (or >= if we want to avoid revisiting with same energy).
  • Use a hash map (or array) to store the maximum energy remaining at each node.
  • Path reconstruction: maintain a parent map or pass the path as a parameter.
  • Edge cases: s == t, no path exists, energy exactly zero at t.
  • Complexity: worst-case exponential, but pruning reduces practical runtime; mention that the problem is NP-hard (related to longest path with resource constraints).
  • Alternative approaches: BFS with priority queue (Dijkstra-like) if we want to maximize energy, but DFS with pruning is simpler for path existence.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Extend the graph problem: now m potions are scattered across rooms, each granting a one-time energy boost on first visit. Find a path from s to t that maximizes rooms visited while keeping energy nonnegative, or report t is unreachable. The graph can have up to 200k nodes and 500k edges. Discuss your approach, correctness, and how you'd optimize it.

Algorithms & Data StructuresTechnical Trade-offsSystem Design
Author's notes

This is where I started sweating.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and define the state as (node, energy, potions collected), but note that energy can be large and potions are one-time. Propose a solution that combines graph traversal with dynamic programming or greedy strategies, leveraging the fact that potions only help and revisiting nodes may be necessary. Discuss how to handle large graphs by using efficient data structures and pruning.

Pro tip: Emphasize that the problem is NP-hard in general (e.g., reduces to longest path), so you'd discuss approximations or special cases, and mention that in practice, you'd use BFS with state compression and priority queues to explore promising paths first.

1. Understand and clarify the problem

Restate the problem: find a walk from s to t maximizing distinct rooms visited, with energy never negative, where potions give one-time boosts. Ask about constraints: can nodes be revisited? Are potions consumed on first visit only? What are energy bounds?

2. Identify complexity and challenges

Recognize that maximizing rooms visited is akin to longest path, which is NP-hard. The energy constraint and one-time potions add state complexity. Discuss that exact solution may be exponential, so consider heuristics or special cases.

3. Propose a baseline approach

Suggest a BFS/DFS with state (node, energy, potions collected) but note state explosion. Alternatively, model as a resource-constrained shortest path where we maximize rooms, using dynamic programming over subsets of potions if m is small.

4. Optimize for large graphs

For large graphs, use A* with a heuristic (e.g., number of unvisited rooms) or greedy exploration: always take potions when possible, and use Dijkstra-like search on (node, energy) with pruning. Mention that energy can be capped at max needed to reach t.

5. Discuss correctness and trade-offs

Explain that the greedy approach may not be optimal, but can be proven optimal under certain conditions (e.g., if potions are abundant). Discuss time/space complexity and potential approximations.

Key Points to Mention

  • NP-hardness of longest path problem and implications for exact solution
  • State space definition: (current node, remaining energy, set of collected potions)
  • Use of BFS/DFS with memoization or dynamic programming for small m
  • Heuristic search (A*) or greedy strategies for large graphs
  • Energy capping: maximum energy needed is bounded by graph size and potion boosts
  • Handling unreachable t: if no path exists even with all potions, report unreachable

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.