← Apple Interview Insights

Apple·Software Engineer·Onsite - System Design / Architecture·Intermediate

Intermediate
May 2026

Summary

Apple SWE interview with a system design and OOD focus. The main problem was designing a deck of cards with shuffle and draw operations, which sounds almost too simple until you actually have to argue about probability guarantees and complexity out loud.

Questions Asked (1)

Q1

Design a deck of playing cards with Card, Deck, and supporting classes (like Suit and Rank enums). Implement shuffle() to produce a uniformly random permutation and draw() to remove and return a card while preserving uniform-random order. Discuss the correctness of the probability argument and the complexity of each operation.

System DesignAlgorithms & Data StructuresTechnical Trade-offs
Author's notes

I started with the class structure which was fine, Suit and Rank as enums, Card as a simple value object, Deck holding a list.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Start by outlining the class design with Card, Deck, Suit, and Rank, then implement shuffle using Fisher-Yates and draw by removing from the end. Explain the uniform random permutation proof and analyze time/space complexity for each operation.

Pro tip: Mention that using a list and swapping in-place avoids extra space, and that drawing from the end is O(1) while preserving uniformity. Also, discuss thread-safety if the deck is shared.

1. Class Design

Define Suit and Rank enums, and a Card class with suit and rank fields. Deck class holds a list of cards and supports shuffle and draw.

2. Shuffle Implementation

Implement Fisher-Yates shuffle: iterate from last index down to 1, swap each card with a randomly chosen card from the remaining unshuffled portion.

3. Draw Implementation

Implement draw by removing and returning the last card from the deck (or first if using a queue), ensuring O(1) time and preserving uniform random order.

4. Correctness Proof

Argue that each permutation is equally likely: at each step, the probability of any remaining card being placed at the current position is 1/(remaining count).

5. Complexity Analysis

Shuffle is O(n) time and O(1) extra space; draw is O(1) time. Discuss trade-offs if using other data structures.

Key Points to Mention

  • Fisher-Yates shuffle algorithm and its uniform random permutation property
  • In-place swapping to achieve O(1) extra space
  • Draw operation should be O(1) by removing from the end of the list
  • Proof of uniformity: each card has equal probability of ending up in any position
  • Time complexity: shuffle O(n), draw O(1); space complexity: O(n) for deck storage
  • Potential thread-safety considerations if deck is accessed concurrently

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.