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Meta·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
May 2026Remote

Summary

Meta SWE coding round, one question on sliding window duplicate detection. Pretty straightforward on the surface but the edge cases around the boundary condition tripped me up a bit.

Questions Asked (1)

Q1

Given an unsorted integer array, a window size K, and a value T, determine whether any two distinct indices i and j exist such that the array values at those indices are equal and the distance between the indices is at most K.

Algorithms & Data Structures
Author's notes

I went straight for a hashmap to track last-seen indices and slid a window of size K across the array.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and edge cases, then propose an efficient solution using a hash map to track the last seen index of each element. Explain that while iterating, if the current element was seen within the last K indices, return true; otherwise update its last seen index. Analyze time and space complexity, and discuss potential optimizations or alternative approaches.

Pro tip: Mention that the hash map approach is optimal for a single query, but if multiple queries with different K are expected, consider preprocessing or using a sliding window with a set. Also, explicitly handle edge cases like K=0 or empty array to show thoroughness.

1. Clarify the problem

Restate the problem in your own words and ask clarifying questions about constraints, such as whether K can be 0, if the array can be empty, and if T is relevant (since the problem only checks equality).

2. Discuss brute force

Acknowledge the naive O(n*K) approach of checking each element against the next K elements, and explain why it's inefficient for large inputs.

3. Propose optimal solution

Describe the hash map approach: iterate through the array, store the last seen index of each element, and check if the current index minus the stored index is <= K. If so, return true; else update the stored index.

4. Analyze complexity

State that the time complexity is O(n) and space complexity is O(min(n, K)) or O(n) in the worst case, and explain why this is optimal.

5. Handle edge cases and test

Walk through edge cases like K=0, empty array, or no duplicates, and mentally test the solution with a small example to ensure correctness.

Key Points to Mention

  • Hash map to store last seen index of each element
  • Time complexity O(n) and space complexity O(n)
  • Sliding window concept: only need to remember elements within the last K indices
  • Edge cases: K=0, empty array, K >= array length, negative numbers
  • Comparison with brute force O(n*K) approach
  • Potential follow-up: if multiple queries with different K, consider preprocessing or using a balanced BST

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.