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Hopper·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

Hopper software engineer interview with a sorting problem that looked simple until you actually thought about it. The follow-ups on edge cases and optimization are where it got interesting.

Questions Asked (3)

Q1

Given a list of filenames, sort them using a custom comparator that puts digit-starting names before letter-starting ones, and compares numeric chunks by their actual numeric value rather than lexicographically.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I started with a naive split on digits vs letters and got the basic comparator working, but I fumbled the explanation of why plain string sort fails for mixed numeric chunks.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the requirements and edge cases, then outline a custom comparator that first checks the first character to prioritize digit-starting filenames. For numeric chunks, parse consecutive digits into integers for comparison, and fall back to lexicographic comparison for non-numeric parts. Finally, discuss complexity, potential pitfalls, and test cases.

Pro tip: Mention that you would use a stable sort to preserve the original order of equal elements, and discuss how to handle leading zeros and very large numbers that might overflow standard integer types.

1. Clarify requirements and edge cases

Ask about the definition of 'digit-starting' (e.g., first character is a digit), how to handle empty strings, and whether filenames can contain multiple numeric chunks. Confirm if the sort should be stable and if case sensitivity matters.

2. Design the comparator logic

Outline a comparator that first compares the first character: if one starts with a digit and the other with a letter, the digit-starting one comes first. If both start with the same type, proceed to compare the strings chunk by chunk.

3. Implement chunk-wise comparison

Traverse both strings simultaneously. When both current characters are digits, extract the full numeric chunk from each, convert to integers (or use string comparison with length and lexicographic rules to avoid overflow), and compare numerically. Otherwise, compare characters lexicographically.

4. Analyze complexity and trade-offs

Discuss time complexity O(n log n * m) where n is number of filenames and m is average length, and space complexity O(1) for the comparator. Mention trade-offs between parsing to integers vs. comparing digit strings to handle large numbers.

5. Test with examples

Walk through test cases: ['file10', 'file2', '2file', '10file', 'a1', '1a'] to verify digit-starting names come first and numeric chunks are ordered correctly. Also test edge cases like leading zeros, empty strings, and mixed alphanumeric chunks.

Key Points to Mention

  • Custom comparator function that can be passed to a sorting algorithm (e.g., Python's sorted with cmp_to_key or Java's Comparator).
  • Handling numeric chunks by comparing their integer values, not lexicographically (e.g., '10' > '2').
  • Avoiding integer overflow by comparing digit chunks as strings: first by length, then lexicographically.
  • Stability of the sort to preserve original order of equal elements.
  • Time and space complexity analysis of the sorting approach.
  • Edge cases: leading zeros, empty strings, filenames with multiple numeric chunks, and case sensitivity.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

How would you handle sorting file01.txt versus file1.txt when leading zeros are involved? Define a rule and justify why it's deterministic.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This tripped me up more than I expected.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the context: are we sorting filenames for display, or comparing them for equality? Then propose a deterministic rule: split the filename into non-numeric and numeric segments, compare non-numeric segments lexicographically, and numeric segments by their integer value (ignoring leading zeros). Justify determinism by showing that the rule yields a total order and that equal numeric values with different leading zeros are treated as equal, so ties are broken by the original string or by a stable sort.

Pro tip: Mention that this is essentially 'natural sort order' and that many languages have built-in functions (e.g., `strverscmp` in C, `natsort` in Python) but you should be prepared to implement it if needed. Also note that determinism requires a consistent tie-breaking rule, such as falling back to lexicographic comparison of the original strings.

1. Clarify requirements

Ask whether the sort is for human consumption (e.g., file listings) or for machine processing (e.g., version comparison). Determine if leading zeros are significant (e.g., in version numbers) or just formatting.

2. Define the comparison rule

Propose a rule: tokenize the filename into alternating non-digit and digit sequences. Compare non-digit tokens lexicographically; compare digit tokens by their numeric value (ignoring leading zeros). If numeric values are equal, fall back to comparing the original digit strings lexicographically to ensure determinism.

3. Justify determinism

Explain that the rule defines a total order because every pair of filenames can be compared, and the comparison is transitive and antisymmetric. The tie-breaking rule ensures that equal numeric values are ordered consistently, so the sort result is unique regardless of input order.

4. Discuss trade-offs and edge cases

Address potential issues: very large numbers (overflow), locale-specific digit characters, and performance (O(n log n) comparisons). Mention that treating leading zeros as insignificant may not be desired in all contexts (e.g., 'file01' vs 'file1' might be considered distinct).

5. Provide an example

Walk through sorting ['file01.txt', 'file1.txt', 'file10.txt', 'file2.txt'] to show the rule in action: file1.txt and file01.txt are equal numerically, so tie-break by original string gives 'file01.txt' before 'file1.txt' (since '0' < '1' lexicographically).

Key Points to Mention

  • Natural sort order (also known as human sort or version sort) is the standard approach for this problem.
  • Tokenization: split into numeric and non-numeric parts to compare appropriately.
  • Determinism requires a total order and a consistent tie-breaking rule (e.g., fallback to lexicographic comparison of original strings).
  • Leading zeros are ignored for numeric comparison but can be used for tie-breaking to ensure uniqueness.
  • Edge cases: numbers too large for integer types, non-ASCII digits, and filenames with multiple numeric segments.
  • Trade-offs: simplicity vs. correctness, performance implications, and whether to use built-in functions or implement custom logic.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

How would you optimize the sorting for very large inputs, specifically by precomputing a key per filename to avoid re-parsing on every comparison?

Algorithms & Data StructuresSystem Design
Author's notes

This is where I actually felt decent.

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AI HintsAI Generated

Suggested Approach

Start by explaining the inefficiency of re-parsing filenames during every comparison in a sort, then propose precomputing a sort key for each filename once and sorting based on those keys. Emphasize the reduction in time complexity from O(n log n * parse_cost) to O(n * parse_cost + n log n * compare_cost), and discuss how to implement this in practice with a decorate-sort-undecorate pattern.

Pro tip: Mention that precomputing keys is especially beneficial when the parsing logic is expensive (e.g., regex or date parsing) and that you can further optimize by using a Schwartzian transform or caching parsed results if the same filenames appear multiple times.

1. Identify the bottleneck

Explain that sorting algorithms perform O(n log n) comparisons, and if each comparison re-parses filenames, the parsing cost dominates. Quantify the impact for large n.

2. Propose precomputation

Suggest computing a sort key for each filename once, storing it alongside the filename, and then sorting based on the precomputed keys.

3. Choose the right data structure

Recommend using an array of tuples (key, filename) or a custom object, and sorting with a comparator that only compares keys. Mention that in languages like Python, you can use the `key` parameter in `sort`.

4. Analyze complexity and trade-offs

Compare the time complexity: original O(n log n * parse_cost) vs optimized O(n * parse_cost + n log n * compare_cost). Discuss memory overhead of storing keys.

5. Consider further optimizations

Mention caching parsed keys if filenames repeat, using a radix sort if keys are integers, or parallelizing the key computation for very large inputs.

Key Points to Mention

  • Decorate-Sort-Undecorate pattern (Schwartzian transform)
  • Time complexity reduction: avoid O(n log n) parsing operations
  • Memory trade-off: storing keys increases space complexity
  • Language-specific features: Python's `key` argument, Java's Comparator.comparing
  • Caching parsed results for repeated filenames
  • Parallelizing key computation for massive datasets

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.