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Use a window function to group consecutive login dates by subtracting a row number from the date, then count the size of each group and take the maximum per user. This approach efficiently handles gaps and works in most SQL dialects.
Pro tip: Mention that you would first clarify whether the table has one row per user per day (deduplicated) and whether the streak should be based on calendar days or 24-hour periods, as this affects the solution.
Confirm the table schema, ensure one row per user per login day, and clarify if consecutive means calendar days or exact 24-hour intervals.
Use ROW_NUMBER() partitioned by user and ordered by login date, then subtract the row number from the date to create a group identifier for consecutive days.
Group by user and the group identifier, count the number of rows in each group to get streak lengths.
Use MAX() on the streak lengths grouped by user, or use ROW_NUMBER() to pick the longest streak if you need the actual dates.
Consider users with no consecutive days, ties for longest streak, and performance implications for large datasets.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.