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Use backtracking to explore each character: if it's '0' or '1', keep it and move on; if it's '*', branch into two recursive calls, one replacing it with '0' and the other with '1'. Collect the resulting strings when the end of the string is reached. This naturally generates all possible combinations.
Pro tip: Mention that the number of results is 2^k where k is the number of '*', so the time complexity is O(2^k * n) and space O(2^k * n) for output; this shows you consider efficiency and scalability.
Confirm the problem: input string with '0', '1', '*'; output all possible binary strings after replacing each '*'. Ask about constraints (e.g., string length, number of '*') to gauge expected complexity.
Decide between backtracking (recursive) or iterative BFS/queue. Backtracking is straightforward and efficient for this problem; explain why it's suitable.
Write a recursive function that processes the string index by index. For non-'*', append the character and recurse; for '*', branch into two recursive calls with '0' and '1'. When index reaches end, add the built string to results.
State time complexity: O(2^k * n) where k is number of '*' and n is string length, because each combination takes O(n) to build. Space complexity: O(2^k * n) for output plus O(n) recursion stack.
Test with no '*', all '*', empty string, and mixed cases. Ensure no duplicates (none here) and correct order (if required).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.