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Tesla·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

Tesla SWE technical screen, two coding questions back to back. Both were more involved than I expected for a phone round, lots of edge case discussion and they pushed on time/space complexity pretty hard.

Questions Asked (2)

Q1

Given a list of integers with length n, check whether it's a permutation of [0, 1, ..., n-1]. You must do it in-place with O(1) extra space, no hash sets, no sorting, and aim for O(n) time.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I went straight to XOR and they seemed okay with that direction, but then they asked me to also handle out-of-range values and duplicates explicitly and I fumbled a bit.

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AI HintsAI Generated

Suggested Approach

Use the array itself as a hash map by cyclically placing each element at its correct index (value equals index). After placement, verify that every element is in its correct position. This achieves O(n) time and O(1) extra space without sorting or hash sets.

Pro tip: Emphasize that the in-place cyclic sort approach modifies the input, so clarify whether the array can be mutated; if not, discuss the trade-off of using O(n) extra space or a different method. Also, mention that early termination during placement can optimize for non-permutations.

1. Clarify constraints and edge cases

Confirm that the array can be modified in-place and discuss edge cases like n=0, n=1, duplicates, and out-of-range values.

2. Explain the cyclic placement algorithm

Iterate through the array; for each index i, while the element at i is within [0, n-1] and not already at its correct position, swap it with the element at its target index.

3. Verify the permutation condition

After placement, check that for every index i, the element equals i. If any mismatch, it's not a permutation.

4. Analyze time and space complexity

Argue that each element is swapped at most once, so total swaps are O(n), and no extra space is used beyond a few variables.

5. Discuss trade-offs and alternatives

Mention that this modifies the input; if modification is not allowed, consider using the sign bit or other in-place marking techniques, but note they may not work for all cases.

Key Points to Mention

  • Cyclic sort / in-place hashing technique
  • Time complexity O(n) due to each element moved at most once
  • Space complexity O(1) extra space
  • Handling of duplicates and out-of-range values
  • Trade-off: input array is mutated
  • Edge cases: empty array, single element, negative numbers

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Implement a power function that computes base raised to an integer exponent without using any library exponentiation. It needs to run in O(log |exp|) time, handle negative exponents, zero cases, and the minimum 32-bit integer value for the exponent.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Classic fast exponentiation, I've done this before.

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AI HintsAI Generated

Suggested Approach

Start by clarifying requirements and edge cases, then explain the binary exponentiation (exponentiation by squaring) algorithm that achieves O(log |exp|) time. Walk through handling negative exponents, zero base/exponent, and the overflow issue with the minimum 32-bit integer exponent, and finally discuss trade-offs and potential optimizations.

Pro tip: Mention that converting the exponent to a long or using unsigned arithmetic avoids overflow when negating INT_MIN, and note that iterative binary exponentiation is often preferred in production for its constant space and simplicity.

1. Clarify Requirements and Edge Cases

Ask about input types (integer vs floating-point base), expected output precision, and confirm that the exponent is a 32-bit signed integer. Identify edge cases: exp = 0, base = 0, negative exponents, and exp = INT_MIN.

2. Explain the Algorithm

Describe binary exponentiation (exponentiation by squaring): repeatedly square the base and halve the exponent, multiplying the result when the current exponent bit is 1. This yields O(log |exp|) time.

3. Handle Negative Exponents and INT_MIN

For negative exponents, compute the positive power and take the reciprocal. To avoid overflow when negating INT_MIN, convert the exponent to a 64-bit integer (e.g., long) or use unsigned arithmetic before negation.

4. Implement and Test

Write clean code (iterative or recursive) with proper handling of edge cases. Test with cases like exp=0, base=0, negative exponents, and exp=INT_MIN to ensure correctness and no overflow.

5. Discuss Trade-offs and Optimizations

Compare iterative vs recursive implementations (space vs readability), and mention potential optimizations like early termination for base 0 or 1, and handling floating-point precision if applicable.

Key Points to Mention

  • Binary exponentiation (exponentiation by squaring) achieves O(log |exp|) time by reducing the exponent by half each step.
  • Negative exponents require computing the reciprocal of the positive power, but careful handling is needed for INT_MIN to avoid overflow.
  • Edge cases: exp = 0 returns 1 (except possibly 0^0, which may be defined as 1), base = 0 with positive exp returns 0, and base = 0 with negative exp is undefined (division by zero).
  • INT_MIN cannot be negated in 32-bit signed arithmetic; use a 64-bit integer or unsigned type to safely handle the negation.
  • Iterative implementation uses O(1) space and avoids recursion overhead, while recursive is O(log |exp|) space due to call stack.
  • Consider precision and overflow if the base is floating-point or if intermediate results exceed the data type's range.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.