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Oracle·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

Oracle SWE interview with a sliding window problem. Pretty standard coding round, nothing too surprising.

Questions Asked (1)

Q1

Given a string and a pattern, find the minimum window substring that contains all characters of the pattern.

Algorithms & Data Structures
Author's notes

Classic sliding window problem.

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AI HintsAI Generated

Suggested Approach

Use a sliding window with two pointers to expand and contract the window while tracking character frequencies. Maintain a count of matched characters to efficiently determine when the window contains all pattern characters, and update the minimum window whenever a valid window is found.

Pro tip: Clarify edge cases upfront (e.g., pattern longer than string, empty inputs) and discuss time/space complexity (O(n) time, O(k) space) to demonstrate thoroughness. Mention that this is the classic 'Minimum Window Substring' problem and that the sliding window approach is optimal.

1. Clarify and Validate

Ask clarifying questions about input constraints, character set (ASCII/Unicode), case sensitivity, and expected output if no valid window exists. Confirm that the window must contain all characters of the pattern, including duplicates.

2. Choose Data Structures

Use a frequency map (e.g., array or hash map) for the pattern and a dynamic frequency map for the current window. Maintain a 'matched' counter to track how many pattern characters are fully satisfied.

3. Sliding Window Expansion

Initialize left and right pointers at 0. Expand the window by moving right, updating the window frequency map and matched counter. When matched equals the number of unique characters in the pattern, a valid window is found.

4. Window Contraction and Optimization

While the window is valid, update the minimum window if the current length is smaller. Then contract from the left by moving left forward, updating the window frequency map and matched counter, until the window is no longer valid.

5. Return Result and Analyze Complexity

After the right pointer reaches the end, return the minimum window substring (or empty string if none). State that time complexity is O(n) and space complexity is O(k), where n is the string length and k is the number of unique characters in the pattern.

Key Points to Mention

  • Sliding window technique with two pointers (left and right) to avoid unnecessary re-scanning.
  • Use of frequency maps (hash map or fixed-size array) to track character counts in the pattern and current window.
  • Maintaining a 'matched' counter to efficiently check if the window contains all pattern characters.
  • Handling duplicates in the pattern by counting required occurrences.
  • Updating the minimum window length and start index whenever a valid window is found.
  • Time complexity O(n) and space complexity O(k), where n is the string length and k is the number of unique characters in the pattern.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.