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Bloomberg·Software Engineer·Onsite - Coding / Algorithms·Intermediate

IntermediatePrefer not to say
May 2026

Summary

Bloomberg SWE coding round, two problems back to back. Nothing too crazy but the second one was sneakier than it looked on the surface.

Questions Asked (2)

Q1

Given an array of distinct integers, return all possible subsets (the power set).

Algorithms & Data Structures
Author's notes

Pretty classic backtracking problem.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints (e.g., array size, distinct integers) and then present a backtracking solution that builds subsets incrementally. Explain the decision at each element (include or exclude) and analyze the time and space complexity.

Pro tip: Mention that the total number of subsets is 2^n, so any algorithm must take at least O(2^n) time; this shows you understand the inherent complexity and sets realistic expectations.

1. Clarify and Confirm

Ask about input size, whether the array can be empty, and if the order of subsets matters. Confirm that the integers are distinct.

2. Choose an Approach

Decide between backtracking, bit manipulation, or iterative expansion. Backtracking is intuitive and easy to explain; bit manipulation is concise but less flexible.

3. Explain the Algorithm

Walk through the chosen approach step-by-step, using a small example to illustrate how subsets are generated.

4. Analyze Complexity

State that time complexity is O(n * 2^n) and space complexity is O(n * 2^n) for the output, plus O(n) for recursion stack.

5. Discuss Trade-offs and Edge Cases

Compare approaches, mention handling of empty input, and note that the solution naturally handles duplicates if they were present (with sorting and skipping).

Key Points to Mention

  • Backtracking with include/exclude decisions at each index.
  • Bit manipulation: each subset corresponds to a binary number from 0 to 2^n - 1.
  • Time complexity: O(n * 2^n) because there are 2^n subsets and each takes O(n) to copy.
  • Space complexity: O(n * 2^n) for storing all subsets, plus O(n) recursion depth.
  • Edge cases: empty array returns [[]], single element returns [[], [x]].
  • Avoiding duplicates: if the array had duplicates, sort and skip same elements at the same recursion level.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given a string that may contain non-parenthesis characters mixed in, determine whether the parentheses in the string form a valid sequence.

Algorithms & Data Structures
Author's notes

Looked easy and I almost said so out loud, which would've been embarrassing.

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AI HintsAI Generated

Suggested Approach

Clarify that only parentheses matter and other characters can be ignored. Use a stack to track opening brackets, ensuring each closing bracket matches the most recent unmatched opening. After processing, verify the stack is empty.

Pro tip: Mention that you can optimize space by using a counter if only one type of parenthesis is present, but a stack is necessary for multiple types. Also, discuss edge cases like empty string or strings with no parentheses.

1. Clarify the problem

Confirm that the string may contain other characters, but only parentheses need to be validated. Ask if there are multiple types of parentheses (e.g., (), [], {}) or just one.

2. Choose data structure

For multiple types, use a stack to track opening brackets. For a single type, a simple counter suffices. Explain the trade-offs.

3. Iterate and validate

Traverse the string. On an opening bracket, push onto the stack (or increment counter). On a closing bracket, check if it matches the top of the stack (or if counter > 0) and pop (or decrement). If mismatch or empty stack, return false.

4. Final check

After traversal, ensure the stack is empty (or counter is zero). If not, return false; otherwise, return true.

5. Analyze complexity

State that time complexity is O(n) and space complexity is O(n) in the worst case (or O(1) for single type with counter).

Key Points to Mention

  • Stack data structure for matching parentheses
  • Ignoring non-parenthesis characters
  • Handling multiple types of parentheses
  • Edge cases: empty string, no parentheses, unbalanced parentheses
  • Time and space complexity analysis
  • Potential optimization using counter for single type

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.