The 'distinct by value not by index' part is what tripped me up initially.
Clarify that we need distinct palindromic subsequences of lengths 2, 3, and 4, counting unique strings. Use combinatorial counting based on character frequencies and positions, avoiding brute-force enumeration of all subsequences. For each length, derive formulas or use sets to ensure uniqueness.
Pro tip: Mention that for length 2, the answer is simply the number of distinct characters that appear at least twice. This shows you can simplify the problem and avoid overcomplicating.
Confirm that we count distinct palindromic strings of lengths 2, 3, and 4, not index combinations. Ask about input size to determine if O(n^2) or O(n) is acceptable.
A length-2 palindrome is two identical characters. Count the number of distinct characters that appear at least twice in the string.
A length-3 palindrome has form c X c. For each character c, count distinct characters X that appear between some occurrence of c and another occurrence of c. Use first and last occurrence positions to determine which X are possible.
A length-4 palindrome has form a b b a. For each pair (a, b), check if there exist indices i < j < k < l with s[i]=a, s[j]=b, s[k]=b, s[l]=a. Use precomputed next/prev occurrence arrays to check efficiently.
Sum the counts for lengths 2, 3, and 4. Test with small examples like 'aaaa' and 'abba' to ensure correctness and uniqueness.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.