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Databricks·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

Databricks SWE interview with a two-part coding problem centered on networking fundamentals. The IP validation part was manageable but the CIDR follow-up required some bitwise thinking that I wasn't fully warmed up for.

Questions Asked (2)

Q1

Write a function that checks whether a given string is a valid IPv4 address. Each octet must be between 0 and 255, and leading zeros should be rejected.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Felt pretty solid on this one.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the exact requirements: IPv4 format, octet range 0-255, no leading zeros, and exactly four octets separated by dots. Then outline a solution that splits the string by '.', validates each part for numeric range and leading zeros, and handles edge cases like empty strings or extra dots. Finally, discuss trade-offs between a simple split-based approach and a more efficient character-by-character parser.

Pro tip: Mention that you would avoid using built-in IP parsing libraries (like inet_aton) because they may accept non-standard formats, and instead implement a strict validator to meet the exact requirements. Also, proactively discuss how you would test edge cases like '01.1.1.1', '256.1.1.1', and '1.1.1.1.1'.

1. Clarify requirements

Confirm that the input is a string, the output is a boolean, and that leading zeros are disallowed (e.g., '01' is invalid). Also confirm that exactly four octets are required and each must be 0-255.

2. Choose an approach

Decide between splitting the string by '.' and validating each part, or parsing character-by-character. Discuss the trade-offs: split is simpler but may create extra strings; character-by-character is more efficient but more complex.

3. Implement validation logic

For each octet, check that it is non-empty, contains only digits, has no leading zeros (unless it is exactly '0'), and its integer value is between 0 and 255. Also ensure there are exactly four octets.

4. Handle edge cases

Test cases like empty string, multiple consecutive dots, trailing dot, octets with leading zeros, values >255, and non-numeric characters. Ensure the function returns false for all invalid inputs.

5. Analyze complexity and trade-offs

State that the time complexity is O(n) where n is the length of the string, and space complexity is O(1) if parsing in place or O(n) if using split. Discuss when a more efficient parser might be needed.

Key Points to Mention

  • Exactly four octets separated by dots.
  • Each octet must be a decimal number between 0 and 255 inclusive.
  • Leading zeros are not allowed (e.g., '01' is invalid, but '0' is valid).
  • Edge cases: empty string, extra dots, non-digit characters, octets >255.
  • Time complexity O(n) and space complexity O(1) or O(n) depending on implementation.
  • Avoid using built-in IP parsers that may accept non-standard formats.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given an IP address and a CIDR block like 192.168.1.0/24, determine whether the IP falls within that CIDR range.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where things got a bit wobbly.

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AI HintsAI Generated

Suggested Approach

Convert both the IP address and the CIDR block's network address to 32-bit integers, then compare the first N bits (where N is the prefix length) using a bitmask. This approach is efficient, handles all cases, and avoids string manipulation.

Pro tip: Mention that you can use bitwise operations (e.g., (ip_int >> (32 - prefix)) == (network_int >> (32 - prefix))) to avoid creating a mask, and discuss how this scales to IPv6 with 128-bit integers.

1. Parse and Validate Input

Split the CIDR block into IP and prefix length, and validate that both the IP and CIDR are well-formed. Handle edge cases like invalid prefix lengths (e.g., >32 for IPv4).

2. Convert to Integer Representation

Convert the IP address and the network address from the CIDR block into 32-bit unsigned integers. This can be done by splitting on dots and combining octets with bit shifts.

3. Apply Bitmask or Shift Comparison

Compute the network mask from the prefix length (e.g., mask = ~((1 << (32 - prefix)) - 1)) and apply it to both IPs, or simply compare the first 'prefix' bits using right shifts.

4. Compare and Return Result

Check if the masked IP equals the masked network address. If they match, the IP is in the CIDR range; otherwise, it is not.

5. Discuss Trade-offs and Extensions

Mention alternative approaches (e.g., using built-in libraries like Python's ipaddress module) and their trade-offs in terms of performance, readability, and dependency. Also note how to extend to IPv6.

Key Points to Mention

  • Bitwise operations and integer conversion for efficiency
  • Handling edge cases: prefix length 0 (matches all) and 32 (exact match)
  • Time and space complexity: O(1) time, O(1) space
  • Alternative approaches using standard libraries (e.g., ipaddress in Python, netaddr)
  • IPv6 extension: using 128-bit integers and similar logic
  • Input validation and error handling for malformed inputs

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.