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Clarify the problem constraints, especially that the first array has enough space to hold the merged result. Then propose an efficient in-place merge using three pointers starting from the end of both arrays to avoid overwriting. Walk through the algorithm, analyze complexity, and discuss edge cases.
Pro tip: Mention that merging from the end is optimal because it avoids shifting elements, and explicitly state that the time complexity is O(m+n) and space is O(1). This shows you understand the trade-offs and can optimize for in-place operations.
Confirm that the first array has sufficient capacity (m+n) and that m and n represent the number of valid elements in each array. Ask if the arrays are sorted in ascending order and if in-place means O(1) extra space.
Explain that merging from the end with three pointers (i, j, k) is optimal because it avoids shifting elements and uses constant extra space. Contrast with merging from the front, which would require extra space or shifting.
Initialize i = m-1, j = n-1, k = m+n-1. While i >= 0 and j >= 0, compare nums1[i] and nums2[j], place the larger at nums1[k], and decrement the corresponding pointer and k. After the loop, if any elements remain in nums2, copy them to the beginning of nums1.
State that time complexity is O(m+n) and space is O(1). Discuss edge cases: one array empty, all elements of one array smaller, duplicates, and negative numbers.
Walk through a simple example like nums1 = [1,2,3,0,0,0], m=3, nums2 = [2,5,6], n=3 to demonstrate correctness. Mention that you would write unit tests for edge cases.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.