The answer is 1, it returns with certainty, same as 1D.
Recognize this as a classic problem in probability theory: a 2D simple symmetric random walk is recurrent, so the probability of eventual return to the origin is 1. Explain the intuition and, if possible, sketch a proof using the divergence of the sum of return probabilities or electrical network theory. Be prepared to contrast with the 1D and 3D cases to demonstrate deeper understanding.
Pro tip: Mention that while the return probability is 1, the expected return time is infinite—this subtlety often impresses interviewers and shows you understand the difference between recurrence and positive recurrence.
Confirm that the walk is simple, symmetric, and on the infinite 2D integer lattice, starting at the origin. Define 'eventually returns' as the probability that the particle hits the origin at some time n > 0.
State that for a simple symmetric random walk, the return probability is 1 in 1D and 2D (recurrent), but less than 1 in 3D and higher (transient).
Explain that in 2D, the number of possible paths grows as 4^n while the probability of being at the origin at time 2n decays as 1/n, leading to a divergent sum of return probabilities, which implies recurrence.
Be ready to discuss the expected return time (infinite) and the contrast with 3D, where the return probability is about 0.34.
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